/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 In Exercises 5 - 16, determine w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises 5 - 16, determine whether the sequence is geometric. If so, find the common ratio. \( \dfrac{1}{5}, \dfrac{2}{7}, \dfrac{3}{9}, \dfrac{4}{11}, \cdots \)

Short Answer

Expert verified
The given sequence is not a geometric sequence as the ratio between consecutive terms is not constant.

Step by step solution

01

Compute ratio for the first two terms

Calculate the ratio of the second term to the first term: \( r_1 = \frac{\dfrac{2}{7}}{\dfrac{1}{5}} = \frac{2}{7} \times \frac{5}{1} = \frac{10}{7} = 1.\overline{428571} \).
02

Compute ratio for the second and third terms

Calculate the ratio of the third term to the second term: \( r_2 = \frac{\dfrac{3}{9}}{\dfrac{2}{7}} = \frac{3}{9} \times \frac{7}{2} = \frac{21}{18} = 1.\overline{16} \) .
03

Compare the ratios

Compare \( r_1 \) and \( r_2 \). If they are equal, sequence is geometric and the common ratio is \( r_1 \) or \( r_2 \). However, here, they are unequal since \( 1.\overline{428571} \ne 1.\overline{16} \). This means the sequence is not geometric.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Common Ratio
The term **common ratio** is essential when discussing geometric sequences. A geometric sequence is a list of numbers where each term is derived from the previous one by multiplying it with a fixed number, known as the common ratio. To determine if a sequence is geometric, you must check if the ratios between successive terms are constant.

For the sequence given in the exercise, which is \( \frac{1}{5}, \frac{2}{7}, \frac{3}{9}, \frac{4}{11}, \cdots \), you find the common ratio by dividing each term by the previous term. If all these ratios are the same, you have a geometric sequence, and that number is your common ratio. But if they're not the same, like in this exercise, the sequence is not geometric.
  • Example: Calculate the common ratio between the first two terms \( \frac{2}{7} \) divided by \( \frac{1}{5} \).
  • If you obtain a different ratio between any pair of successive terms, there is no common ratio.
Mathematical Sequence
Understanding what a **mathematical sequence** is can significantly help in solving sequence-related problems. A sequence is an ordered set of numbers following a specific rule, and can be finite or infinite.

In a sequence, each number is called a term. There are different types of sequences, but the most common are arithmetic and geometric sequences. In an arithmetic sequence, each term is the addition of a fixed number to the previous term. Conversely, a geometric sequence uses multiplication with a fixed ratio, known as the common ratio, to achieve subsequent terms.
  • Arithmetic Sequence Example: 2, 4, 6, 8 (difference is 2)
  • Geometric Sequence Example: 3, 6, 12, 24 (common ratio is 2)
Thus, to categorize a given sequence as geometric, consistency of the common ratio is essential.
Ratio Calculation
**Ratio calculation** is a simple yet highly integral process when working with sequences. It's especially important in identifying geometric sequences. To calculate a ratio, dividing one magnitude by another gives you a figure that represents how many times the second term fits into the first.

For sequence problems like the one presented, you calculate the ratio between consecutive terms to determine if it's geometric. For example, for the sequence provided:
  • First calculate: \( r_1 = \frac{\left( \frac{2}{7} \right)}{\left( \frac{1}{5} \right)} = \frac{10}{7} \)
  • Then calculate: \( r_2 = \frac{\left( \frac{3}{9} \right)}{\left( \frac{2}{7} \right)} = \frac{21}{18} \)
  • Comparing \( r_1 \) and \( r_2 \), they must be equal for the sequence to be geometric.
In situations where these calculations yield different results, as shown in this exercise, the sequence cannot be geometrically classified.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 53 - 60, the sample spaces are large and you should use the counting principles discussed in Section 9.6. The deck for a card game is made up of \( 108 \) cards. Twenty-five each are red, yellow, blue,and green, and eight are wild cards. Each player is randomly dealt a seven-card hand. (a) What is the probability that a hand will contain exactly two wild cards? (b) What is the probability that a hand will contain two wild cards, two red cards, and three blue cards?

American roulette is a game in which a wheel turns on a spindle and is divided into \( 38 \) pockets.Thirty-six of the pockets are numbered \( 1-36 \), of which half are red and half are black. Two of the pockets are green and are numbered \( 0 \) and \( 00 \) (see figure). The dealer spins the wheel and a small ball in opposite directions. As the ball slows to a stop, it has an equal probability of landing in any of the numbered pockets. (a) Find the probability of landing in the number \( 00 \) pocket. (b) Find the probability of landing in a red pocket. (c) Find the probability of landing in a green pocket or a black pocket. (d) Find the probability of landing in the number \( 14 \) pocket on two consecutive spins. (e) Find the probability of landing in a red pocket on three consecutive spins.

In Exercises 53 - 60, the sample spaces are large and you should use the counting principles discussed in Section 9.6. A class is given a list of \( 20 \) study problems, from which \( 10 \) will be part of an upcoming exam. A student knows how to solve \( 15 \) of the problems. Find the probabilities that the student will be able to answer (a) all \( 10 \) questions on the exam, (b)exactly eight questions on the exam, and (c) at least nine questions on the exam.

Two integers from 1 through 40 are chosen by a random number generator. What are the probabilities that (a) the numbers are both even, (b) one number is even and one is odd, (c) both numbers are less than 30, and (d) the same number is chosen twice?

In Exercises 51 - 56, evaluate \( _nC_r \) using the formula from this section. \( _{20}C_0 \)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.