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Two integers from 1 through 40 are chosen by a random number generator. What are the probabilities that (a) the numbers are both even, (b) one number is even and one is odd, (c) both numbers are less than 30, and (d) the same number is chosen twice?

Short Answer

Expert verified
The probabilities are as follows: (a) 25%, (b) 50%, (c) approximately 52.28%, and (d) 2.5%.

Step by step solution

01

Calculation of Total Possible Outcomes

The first step is to figure out the total number of outcomes. The range is from 1 to 40. Each number can be chosen again after it has been chosen once. This means each choice has 40 options, resulting in a total of \(40 * 40 = 1600\) possible outcomes.
02

Calculation of Probability for Scenario (a)

For scenario (a), both numbers need to be even. The total even numbers from 1 to 40 are 20. So the probability is \( \frac{{20 * 20}}{{1600}} = 0.25\) or 25%
03

Calculation of Probability for Scenario (b)

For scenario (b), one number needs to be even and one odd. There are 20 even numbers and 20 odd numbers. There are two ways this can happen, either the first number is even and the second odd or vice versa. This results in a probability of \( \frac{{20 * 20 * 2}}{{1600}} = 0.5\) or 50%
04

Calculation of Probability for Scenario (c)

In scenario (c), both numbers need to be less than 30. The numbers less than 30 range from 1 to 29 inclusive which results in 29 such numbers. So, the probability is \( \frac{{29 * 29}}{{1600}} = 0.5228125\) or approximately 52.28%.
05

Calculation of Probability for Scenario (d)

In scenario (d), the same number needs to be chosen twice. There are 40 such numbers that can be picked. So, the probability is \( \frac{{40}}{{1600}} = 0.025\) or 2.5%

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Random Number Generator
When tackling probability problems, understanding what a random number generator (RNG) does is crucial. An RNG is a computational or physical device designed to generate a sequence of numbers that lack any discernible pattern. This randomness is essential for making sure that each number has an equal chance of being selected. In the context of our problem, an RNG selecting two integers from 1 through 40 ensures that all 1600 outcomes are equally probable.

Imagine rolling a fair, 40-sided die twice; this would be a physical equivalent of our digital RNG scenario. The critical point to remember is that an RNG doesn't remember previous choices, which is why the second number picked doesn't depend on the first. This idea underlies the fundamental principle of independent events in probability theory.
Even and Odd Integers
Breaking down the concept of even and odd integers simplifies many probability problems. An even integer is any number that can be divided by 2 without leaving a remainder, such as 2, 4, or 36. Conversely, an odd integer has a remainder of 1 when divided by 2, like 1, 3, or 35. In our exercise, integers from 1 to 40 are split evenly between even and odd, with 20 of each.

Understanding evens and odds leads to the realization that there is a symmetry in choices, facilitating calculations. For example, since there are 20 even and 20 odd numbers in the range of 1 to 40, the chance of picking one even and one odd (as in scenario b) is the same as picking one odd and then one even, doubling the number of favorable outcomes (from 20 x 20 to 40 x 20).
Probabilities in Precalculus
Grasping probabilities in precalculus sets a solid foundation for more complex mathematics. Probability can be thought of as a way to measure the likelihood of an event happening, often expressed as a fraction, a percentage, or a ratio. The basic idea is to compare the favorable outcomes to the total possible outcomes.

For instance, to determine the probability of both numbers being even (scenario a), we see that 20 out of 40 integers are even, giving us 20 favorable outcomes for the first number and 20 for the second, resulting in a probability of 25% when calculated against the total 1600 outcomes. In more advanced scenarios, understanding combinations, permutations, and other more complex probabilistic models are required. For now, knowing the basics is enough to solve typical precalculus problems.

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