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In Exercises 45 - 66, use the properties of logarithms to expand the expression as a sum, difference, and/or constant multiple of logarithms. (Assume all variables are positive.) \( \ln 4x \)

Short Answer

Expert verified
\( \ln 4 + \ln x \)

Step by step solution

01

Identify the components

In the expression \( \ln 4x \), there are two factors within the logarithm, which are 4 and \( x \).
02

Apply the Product Rule

The product rule states that \( \ln (ab) \) equals \( \ln a + \ln b \). Applying the product rule to \( \ln 4x \) gives \( \ln 4 + \ln x \).
03

Simplify the Logarithmic Expression

The logarithm of 4 or \( \ln 4 \) is a constant value, so the expression does not need further simplification.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Expressions
Understanding logarithmic expressions is key to working with various mathematical problems involving exponential functions. A logarithmic expression represents the exponent by which a base number is raised to obtain a certain value. For example, in the expression \( \log_b(x) \), the base is \( b \), and \( x \), is the result of raising \( b \) to the power of the logarithm.

In the given exercise, when expanding \( \ln 4x \), we're dealing with the natural logarithm, which means our base is the irrational number \( e \), approximately 2.718. The expression is saying, effectively, 'to what power do we raise \( e \) to get \( 4x \)?' Unlike arithmetic with numbers, logarithms require specific rules and properties to work with effectively, such as the product, quotient, and power rules.

When simplifying logarithmic expressions, you're often converting a single log of a complex quantity into a series of logs of simpler quantities added or subtracted from each other. In the step-by-step solution to our example problem, the product rule is applied to split the logarithm of a product into separate logarithms.
Product Rule of Logarithms
The product rule of logarithms is a vital tool in manipulating and simplifying logarithmic expressions. It states that the logarithm of a product is the sum of the logarithms of the factors. Mathematically, this is expressed as \( \log_b(mn) = \log_b(m) + \log_b(n) \), where \( b \), \( m \) and \( n \) represent real positive numbers, and \( b \) is not equal to 1.

Applying the Product Rule

In the provided example, \( \ln(4x) \), we recognize '4' and 'x' as two separate factors of the product within the logarithm. Following the rule, we can rewrite it as \( \ln(4) + \ln(x) \), demonstrating the application of the product rule.

It's important to recognize that each part of the expression, \( \ln(4) \), and \( \ln(x) \), can be treated and simplified individually, which is a powerful advantage when solving more complex expressions. As per the exercise improvement advice, clearly identifying and separating each factor can make this process easier to understand and follow.
Natural Logarithm
The natural logarithm is a specific type of logarithm where the base is \( e \), the natural exponential function, which is approximately 2.71828. Denoted as \( \ln \), the natural logarithm is the power to which \( e \) must be raised to obtain a number. For instance, if \( e^x = y \), then \( \ln(y) = x \).

Why 'Natural'?

This logarithm is called 'natural' because it arises naturally in mathematics, particularly in calculus, when dealing with growth processes, such as compound interest, population growth, or decay processes. The natural logarithm has a fundamental relationship with the number \( e \), similar to how base-10 logarithms are related to the number 10.

In our exercise example, \( \ln(4x) \), uses this natural logarithm, signifying a growth process with a factor of '4x'. After applying the product rule, the logarithm of a constant, \( \ln(4) \), will remain as it is since it describes a fixed rate of growth, while the \( \ln(x) \) part will generally depend on the value of 'x'. Understanding how to work with natural logarithms is essential in calculus and higher-level mathematics.

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Most popular questions from this chapter

In Exercises 63 and 64, use the Richter scale \( R = \log\dfrac{I}{I_0} \) for measuring the magnitudes of earthquakes. Find the magnitude \( R \) of each earthquake of intensity \( I \) \( \left(let I_0 = 1\right) .\) (a) \( I = 199,500,000 \) (b) \( I = 48,275,000 \) (c) \( I = 17,000 \)

At \( 8:30 \) A.M., a coroner was called to the home of a person who had died during the night. In order to estimate the time of death, the coroner took the persons temperature twice. At \( 9:00 \) A.M. the temperature was \( 85.7^\circ F \) and at \( 11:00 \) A.M. the temperature was \( 82.8^\circ F \). From these two temperatures,the coroner was able to determine that the time elapsed since death and the body temperature were related by the formula \( t = -10 ln \dfrac{T - 70}{98.6 - 70} where \) t \( is the time in hours elapsed since the person died and \) T \( is the temperature (in degrees Fahrenheit) of the persons body. (This formula is derived from a general cooling principle called Newtons Law of Cooling. It uses the assumptions that the person had a normal body temperature of \) 98.6^\circ F \( at death, and that the room temperature was a constant \) 70^\circ F $. ) Use the formula to estimate the time of death of the person.

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In Exercises 81 - 112, solve the logarithmic equation algebraically. Approximate the result to three decimal places. \( \log 3z = 2 \)

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