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In Exercises 37 - 44, find the domain, \( x \)-intercept, and vertical asymptote of the logarithmic function and sketch its graph. \( y = \log(-x) \)

Short Answer

Expert verified
The domain of the function \( y = \log(-x) \) is \( x<0 \). The x-intercept is at \( x=-1 \). The function has a vertical asymptote at \( x = 0 \).

Step by step solution

01

Find the Domain

The domain of a function is all the possible values of \( x \) that will give you real numbers. In logarithmic functions, you cannot take the log of a negative number or zero, only positive numbers. But for this particular function, the inside of the log function is \( -x \). Therefore, the domain will be all \( x \) that make \( -x \) positive, or in other words, all negative numbers.This means that the domain of \( y = \log(-x) \) is \( x<0 \).
02

Find the x-Intercepts

The x-intercept is the value of \( x \) where the function crosses or touches the x-axis. This happens when \( y = 0 \). Here, we set the function equal to 0 and solve for \( x \).0 = log(-x)Converting the equation from logarithmic to exponential form, it becomes \( -x = 10^0 \), this means \( x = -1 \), which is the x-intercept of the function.
03

Find the Vertical Asymptote

The vertical asymptote of a logarithmic function is the value of \( x \) where the function goes to negative or positive infinity. Since the inside of our logarithmic function is \( -x \), which should be positive for real values of the function, there will be a vertical asymptote where \( -x = 0 \) or \( x = 0 \). This is the line that the function gets arbitrarily close to but never touches.
04

Sketch the Graph

To sketch the function, start by drawing the vertical asymptote at \( x = 0 \). Next, point out the x-intercept at \( x = -1 \), and then sketch the curve of the logarithmic function, which should start from the x-intercept and approach but never touch the vertical asymptote, extending upwards to \( y = \inf \) as \( x \) becomes more negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain of a Function
Understanding the domain of a function is crucial because it lets us know which values of \( x \) can be used in the function without resulting in an error. In the case of logarithmic functions like \( y = \log(-x) \), the rules of logarithms dictate that you cannot take the logarithm of zero or any negative number.

However, since the function here is \( \log(-x) \), you're actually looking for values of \( x \) that make \( -x \), the argument inside the log, positive. This means that \( x \) needs to be negative because multiplying a negative by another negative creates a positive.

Therefore, the domain for \( y = \log(-x) \) is all negative real numbers, or simply \( x < 0 \). Always remember:
  • The argument of the log function must be positive.
  • Identify transformations like "\(-x\)" to set the domain correctly.
Vertical Asymptote
A vertical asymptote in a logarithmic function is a line that the graph approaches but fundamentally never touches. It indicates where the function's value becomes infinitely large, either positively or negatively.

For the function \( y = \log(-x) \), the vertical asymptote occurs where the inside of the log function, or \(-x\), equals zero. Solving for \( x \) gives us \( x = 0 \). This means that at \( x = 0 \), the function is undefined because logarithms cannot process zero, and the graph will twirl toward infinity.

Key points to note:
  • Vertical asymptotes occur where the log's argument would equal zero.
  • It acts as a boundary; you can't include the asymptote value in the function's domain.
X-Intercept
The \( x \)-intercept is the point where the graph of a function crosses the \( x \)-axis. Finding the \( x \)-intercept involves setting \( y = 0 \) and solving for \( x \).

In the function \( y = \log(-x) \), setting \( y = 0 \) gives us:\[0 = \log(-x)\]This logarithmic equation can be converted into its exponential form. Using the fact that the base of a common logarithm is 10, the equation becomes:\[-x = 10^0 = 1\]Thus, \( x = -1 \). Hence, the \( x \)-intercept occurs at the point \(( -1, 0 )\). This is where the graph touches the \( x \)-axis.
  • Set \( y = 0 \) to find \( x \)-intercepts in general.
  • Use exponential form conversion for logs: \( \log_b(x) = y \) turns into \( x = b^y \).
Graph Sketching
Graphing a function like \( y = \log(-x) \) involves visualizing how the function behaves over its domain and near its asymptotes. Here's a simple guide:
  • Start by drawing the vertical asymptote at \( x = 0 \). This is your line of limitation.
  • Place the \( x \)-intercept at \( x = -1 \), \( y = 0 \). Mark this point clearly on the graph.
  • Sketch the curve, beginning from the \( x \)-intercept. It will swoop upwards, gently curving as \( x \) becomes more negative.
  • The function will approach the vertical asymptote but shall never touch or cross it, always climbing toward \( y = \infty \).
Remember that the curve echoes the properties of logarithmic functions, growing very slowly and never actually reaching \( x = 0 \). Utilize graphing software or tools for a clearer visualization if you're unsure.

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