Chapter 9: Problem 12
Find the inverse, if it exists, for each matrix. $$\left[\begin{array}{rr} 1 & -1 \\ 2 & 0 \end{array}\right]$$
Short Answer
Expert verified
The inverse is \[ \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \ \end{bmatrix} \]
Step by step solution
01
- Write down the matrix
The given matrix A is \[ A = \begin{bmatrix} 1 & -1 \ 2 & 0 \ \right] \]
02
- Find the determinant of the matrix
To find the inverse of a matrix, we first need to compute its determinant. The determinant of matrix A, denoted as \( \text{det}(A) \), for a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \ \end{bmatrix} \) is given by: \[ \text{det}(A) = ad - bc \] Substituting the values from the matrix, we get: \[ \text{det}(A) = 1 * 0 - (-1) * 2 = 0 + 2 = 2 \]
03
- Check if the determinant is non-zero
Since the determinant is 2, which is not equal to zero, the matrix is invertible.
04
- Find the inverse matrix formula
For a 2x2 matrix \( \begin{bmatrix} a & b \ c & d \ \end{bmatrix} \), the inverse can be found using the formula: \[ A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \ \end{bmatrix} \]
05
- Substitute the values to find the inverse
Using the determinant 2 and the values from matrix A, we can find the inverse: \[ A^{-1} = \frac{1}{2} \begin{bmatrix} 0 & 1 \ -2 & 1 \ \end{bmatrix} \]
06
- Simplify the inverse matrix
Simplify the elements of the inverse matrix by multiplying each entry by \( \frac{1}{2} \): \[ A^{-1} = \begin{bmatrix} 0 \times \frac{1}{2} & 1 \times \frac{1}{2} \ -2 \times \frac{1}{2} & 1 \times \frac{1}{2} \ \end{bmatrix} = \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \ \end{bmatrix} \]
07
Final Answer
The inverse of the matrix is \[ \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \ \end{bmatrix} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
matrix inverse
Calculating the inverse of a matrix is essential in various mathematical applications, including solving systems of linear equations. A matrix inverse, represented as \( A^{-1} \), is a matrix that, when multiplied with the original matrix \( A \), yields the identity matrix \( I \). This unique property makes the inverse extremely useful.
In other words, if you have a matrix \( A \), and you find its inverse \( A^{-1} \), then \( A \cdot \ A^{-1} = I \), where \( I \) is the identity matrix.
Not all matrices have inverses. A matrix must be square (same number of rows and columns) and its determinant must not be zero.
To find an inverse, follow these steps:
In other words, if you have a matrix \( A \), and you find its inverse \( A^{-1} \), then \( A \cdot \ A^{-1} = I \), where \( I \) is the identity matrix.
Not all matrices have inverses. A matrix must be square (same number of rows and columns) and its determinant must not be zero.
To find an inverse, follow these steps:
- Compute the determinant of the matrix.
- Check if the determinant is non-zero.
- Apply the inverse matrix formula.
determinant of a matrix
The determinant of a matrix is a special number that can tell us several properties about the matrix. For a 2x2 matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant is calculated as \( \text{det}(A) = ad - bc \).
The determinant helps to determine if a matrix is invertible. If the determinant is zero, the matrix is non-invertible and is called a singular matrix. If the determinant is non-zero, the matrix is invertible.
In our example, the given matrix is \( \begin{bmatrix} 1 & -1 \ 2 & 0 \end{bmatrix} \).
By applying the determinant formula:
\( \text{det}(A) = 1 \cdot 0 - (-1) \cdot 2 = 0 + 2 = 2 \).
Since the determinant is 2 - not zero - the matrix has an inverse!
The determinant helps to determine if a matrix is invertible. If the determinant is zero, the matrix is non-invertible and is called a singular matrix. If the determinant is non-zero, the matrix is invertible.
In our example, the given matrix is \( \begin{bmatrix} 1 & -1 \ 2 & 0 \end{bmatrix} \).
By applying the determinant formula:
\( \text{det}(A) = 1 \cdot 0 - (-1) \cdot 2 = 0 + 2 = 2 \).
Since the determinant is 2 - not zero - the matrix has an inverse!
2x2 matrix inverse
For a 2x2 matrix, finding the inverse involves a straightforward process. Let's consider the matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \).
First, calculate the determinant \( \text{det}(A) = ad - bc \).
If \( \text{det}(A) \) is non-zero, use the following formula to find the inverse matrix:
\( A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \).
Let's substitute the values from our example matrix, \( \begin{bmatrix} 1 & -1 \ 2 & 0 \end{bmatrix} \):
\( A^{-1} = \frac{1}{2} \begin{bmatrix} 0 & 1 \ -2 & 1 \end{bmatrix} \).
Lastly, we simplify each element:
\( A^{-1} = \begin{bmatrix} 0 \times \frac{1}{2} & 1 \times \frac{1}{2} \ -2 \times \frac{1}{2} & 1 \times \frac{1}{2} \end{bmatrix} = \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \end{bmatrix} \).
The inverse of the matrix is \( \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \end{bmatrix} \). This step-by-step process ensures your calculation is accurate and your matrix inversion is successful!
First, calculate the determinant \( \text{det}(A) = ad - bc \).
If \( \text{det}(A) \) is non-zero, use the following formula to find the inverse matrix:
\( A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \).
Let's substitute the values from our example matrix, \( \begin{bmatrix} 1 & -1 \ 2 & 0 \end{bmatrix} \):
\( A^{-1} = \frac{1}{2} \begin{bmatrix} 0 & 1 \ -2 & 1 \end{bmatrix} \).
Lastly, we simplify each element:
\( A^{-1} = \begin{bmatrix} 0 \times \frac{1}{2} & 1 \times \frac{1}{2} \ -2 \times \frac{1}{2} & 1 \times \frac{1}{2} \end{bmatrix} = \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \end{bmatrix} \).
The inverse of the matrix is \( \begin{bmatrix} 0 & \frac{1}{2} \ -1 & \frac{1}{2} \end{bmatrix} \). This step-by-step process ensures your calculation is accurate and your matrix inversion is successful!