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Find all complex zeros of each polynomial function. Give exact values. List multiple zeros as necessary. $$f(x)=x^{3}-14 x+8$$

Short Answer

Expert verified
The complex zeros are \(x = 2, \; -1 + \sqrt{5}, \; -1 - \sqrt{5} \).

Step by step solution

01

Use the Rational Root Theorem

The Rational Root Theorem suggests that any rational root of the polynomial \(f(x) = x^3 - 14x + 8\) must be a factor of the constant term (8) divided by a factor of the leading coefficient (1). The potential rational roots are \(\text{±1, ±2, ±4, ±8} \).
02

Test possible rational roots

Test the possible rational roots using synthetic division. First, let's test \(x = 1\). Perform the synthetic division: \[ \begin{array}{r|rrr} 1 & 1 & 0 & -14 & 8 \ & & 1 & 1 & -13 & -5 \ \hline & 1 & 1 & -13 & -5 \end{array} \] Since the remainder is not zero, \(x = 1 \) is not a root. Repeat the process for \(x = -1, 2, -2, 4, -4, 8, -8 \).
03

Confirm root found

Testing \(x = 2\): \[ \begin{array}{r|rrr} 2 & 1 & 0 & -14 & 8 \ & & 2 & 4 & -20 & -24 \ \hline & 1 & 2 & -10 & 0 \end{array} \] The remainder is zero, so \(x = 2\) is a root.
04

Factor out the root

Since \(x = 2\) is a root, we can factor out \(x - 2\): \ \(f(x) = (x - 2)(x^2 + 2x - 4)\).
05

Solve the quadratic equation

Solve the quadratic equation \(x^2 + 2x - 4 = 0\) using the quadratic formula: \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 1, b = 2, c = - 4\). \ \ \[x = \frac{-2 \pm \sqrt{4 + 16}}{2} = \frac{-2 \pm \sqrt{20}}{2} = \frac{-2 \pm 2\sqrt{5}}{2} = -1 \pm \sqrt{5} \] Thus, the roots are \(x = -1 \pm \sqrt{5}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Root Theorem
The Rational Root Theorem is a valuable tool in determining potential rational zeros of a polynomial. Here’s how it works: If you have a polynomial equation like \( f(x) = x^3 - 14x + 8 \), the theorem tells us that any rational root, \( p/q \), must be a factor of the constant term (here 8) divided by a factor of the leading coefficient (here 1).
So, for our example, the possible rational roots are:
  • \( \pm 1 \)
  • \( \pm 2 \)
  • \( \pm 4 \)
  • \( \pm 8 \)
By testing these values, we can find out if they are indeed the roots of the polynomial.
Synthetic Division
Once you have potential rational roots, synthetic division helps quickly verify if they are actual roots. Synthetic division is an efficient way to divide polynomials. Let’s break it down through an example. Suppose we want to test whether \( x = 2 \) is a root of \( f(x) = x^3 - 14x + 8 \). We set up the synthetic division:
  • Write down the coefficients of the polynomial: \( 1, 0, -14, 8 \)
  • Place 2 (the potential root) to the left
  • Perform the synthetic division process, where we bring down the first coefficient (1), and then repeatedly multiply and add:
\ \begin{array}{r|rrr} 2 & 1 & 0 & -14 & 8 \ & & 2 & 4 & -20 & -24 \ \hline & 1 & 2 & -10 & 0 \end{array}
The remainder is 0, confirming that \( x = 2 \) is indeed a root. When the remainder is zero, it shows that the value you tested is a root. If it’s not zero, you just move on to the next potential root.
Quadratic Formula
After finding a root using the Rational Root Theorem and synthetic division, factor it out. You might be left with a quadratic equation. In our example, factoring out \( x - 2 \) gives us \( (x - 2)(x^2 + 2x - 4) \). To find the remaining roots, solve the quadratic equation using the quadratic formula:
  • The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
  • Identify the coefficients: for \( x^2 + 2x - 4 \) , \( a = 1, b = 2, \) and \( c = -4 \)
Plug these into the formula:
\[ x = \frac{-2 \pm \sqrt{4 + 16}}{2} \]
Simplify further:
\[ x = \frac{-2 \pm \sqrt{20}}{2} = \frac{-2 \pm 2 \sqrt{5}}{2} = -1 \pm \sqrt{5} \]
Thus, the quadratic formula gives us the remaining complex zeros \( x = -1 \pm \sqrt{5} \). Using these steps, you can systematically find complex zeros for any polynomial.

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Most popular questions from this chapter

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