/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 124 Consider the following "monster"... [FREE SOLUTION] | 91Ó°ÊÓ

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Consider the following "monster" rational function. $$f(x)=\frac{x^{4}-3 x^{3}-21 x^{2}+43 x+60}{x^{4}-6 x^{3}+x^{2}+24 x-20}$$ Analyzing this function will synthesize many of the concepts of this and earlier chapters. Work Exercises \(119-128\) in order. What is the \(y\) -intercept of the graph of \(f ?\)

Short Answer

Expert verified
The y-intercept is -3.

Step by step solution

01

- Understanding the y-intercept

The y-intercept of a function is the point where the graph of the function intersects the y-axis. This occurs when the value of x is zero.
02

- Substitute x with 0 in the function

To find the y-intercept, substitute x = 0 into the function \( f(x) = \frac{x^{4} - 3 x^{3} - 21 x^{2} + 43 x + 60}{x^{4} - 6 x^{3} + x^{2} + 24 x - 20} \) Replace x with 0: \( f(0) = \frac{0^{4} - 3(0)^{3} - 21(0)^{2} + 43(0) + 60}{0^{4} - 6(0)^{3} + 0^{2} + 24(0) - 20} \) Simplify the terms.
03

- Simplify the numerator and denominator

Simplify the function after substituting x = 0: \( f(0) = \frac{60}{-20} \)
04

- Calculate the value

Divide the simplified terms: \( f(0) = \frac{60}{-20} = -3 \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
Rational functions are expressions that involve the division of two polynomials. In simpler terms, a rational function has the form: \[ f(x) = \frac{P(x)}{Q(x)} \] where * \(P(x)\) and \(Q(x)\) are polynomials * \(Q(x)\) is not equal to zero The degrees of these polynomials can be used to analyze various characteristics of the function, such as its intercepts, asymptotes, and end behavior. Remember, a rational function can take many complex forms. Even though they might appear intimidating, breaking them down step-by-step makes them more approachable and easier to understand.
Y-Intercept
The y-intercept of a function is the point where the graph intersects the y-axis. This occurs at x = 0. To find the y-intercept for any function, substitute x = 0 into the function and solve for y. In this exercise, the function is: \[ f(x) = \frac{x^4 - 3x^3 - 21x^2 + 43x + 60}{x^4 - 6x^3 + x^2 + 24x - 20} \] Plugging in x = 0 simplifies the function significantly. All terms containing x will be zero, leaving: \[ f(0) = \frac{60}{-20} \rightarrow f(0) = -3 \] This means the y-intercept of the function is -3. Thus, the graph of the function intersects the y-axis at the point (0, -3).
Function Evaluation
Function evaluation involves finding the value of a function for a given input. When evaluating a function, simply replace the variable with the given input and perform the operations. Here's the process using the provided function: 1. Begin with the rational function: \[ f(x) = \frac{x^4 - 3x^3 - 21x^2 + 43x + 60}{x^4 - 6x^3 + x^2 + 24x - 20} \] 2. To find the y-intercept, set \(x = 0\): \[ f(0) = \frac{0^4 - 3(0)^3 - 21(0)^2 + 43(0) + 60}{0^4 - 6(0)^3 + (0)^2 + 24(0) - 20} = \frac{60}{-20} \] 3. Simplify the fraction to get: \[ f(0) = -3 \] This procedure can be used to evaluate many types of functions, helping to identify key characteristics like intercepts, critical points, and more. Function evaluation is a fundamental skill in algebra and calculus, and practice will make it second nature.

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Most popular questions from this chapter

Match the rational function in Column I with the appropriate description in Column II. Choices in Column II can be used only once. A. The \(x\) -intercept is \(-3\) B. The \(y\) -intercept is 5 C. The horizontal asymptote is \(y=4\) D. The vertical asymptote is \(x=-1\) E. There is a "hole" in its graph at \(x=-4\) F. The graph has an oblique asymptote. G. The \(x\) -axis is its horizontal asymptote, and the \(y\) -axis is not its vertical asymptote. H. The \(x\) -axis is its horizontal asymptote, and the \(y\) -axis is its vertical asymptote. $$f(x)=\frac{x+7}{x+1}$$

Solve each problem. Births to Unmarried Women The percent of births to unmarried women in the United States from 1996 to 2007 are shown in the table. The data are modeled by the quadratic function $$ f(x)=0.0773 x^{2}-0.2115 x+32.64 $$ where \(x=0\) corresponds to 1996 and \(f(x)\) is the percent. If this model continues to apply, what would it predict for the percent of these births in \(2012 ?\) \begin{equation}\begin{array}{c|c||c|c} \text { Year } & \text { Percent } & \text { Year } & \text { Percent } \\ \hline 1996 & 32.4 & 2002 & 34.0 \\ \hline 1997 & 32.4 & 2003 & 34.6 \\ \hline 1998 & 32.8 & 2004 & 35.8 \\ \hline 1999 & 33.0 & 2005 & 36.9 \\ \hline 2000 & 33.2 & 2006 & 38.5 \\ \hline 2001 & 33.5 & 2007 & 39.7 \\ \hline \end{array}\end{equation}

In \(1545,\) a method of solving a cubic equation of the form $$x^{3}+m x=n$$ developed by Niccolo Tartaglia, was published in the Ars Magna, a work by Girolamo Cardano. The formula for finding the one real solution of the equation is $$x=\sqrt[3]{\frac{n}{2}+\sqrt{\left(\frac{n}{2}\right)^{2}+\left(\frac{m}{3}\right)^{3}}}-\sqrt[3]{\frac{-n}{2}+\sqrt{\left(\frac{n}{2}\right)^{2}+\left(\frac{m}{3}\right)^{3}}}$$ (Source: Gullberg, J., Mathematics from the Birth of Numbers, W.W. Norton \& Company.) Use the formula to solve each equation for the one real solution. $$x^{3}+9 x=26$$

Solve each problem.The illumination produced by a light source varies inversely as the square of the distance from the source. The illumination of a light source at \(5 \mathrm{m}\) is 70 candela. What is the illumination \(12 \mathrm{m}\) from the source?

Suppose the effects of detonating a nuclear bomb will be felt over a distance from the point of detonation that is directly proportional to the cube root of the yield of the bomb. Suppose a 100 -kiloton bomb has certain effects to a radius of \(3 \mathrm{km}\) from the point of detonation. Find the distance to the nearest tenth that the effects would be felt for a 1500 -kiloton bomb.

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