Chapter 3: Problem 38
For each polynomial function, use the remainder theorem and synthetic division to find \(f(k) .\) See Example 2 $$f(x)=x^{2}-x+3 ; k=3-2 i$$
Short Answer
Expert verified
The value of \( f(3 - 2i) \) is \( 5 - 10i \).
Step by step solution
01
Understand the problem
We need to find the value of the polynomial function at a given complex number using the remainder theorem and synthetic division. The function is given as \( f(x) = x^2 - x + 3 \) and we have \( k = 3 - 2i \).
02
Apply the remainder theorem
The remainder theorem states that if a polynomial \( f(x) \) is divided by \( x - k \), the remainder of this division is \( f(k) \). Thus, we need to evaluate \( f \) at \( k = 3 - 2i \).
03
Set up synthetic division
Set up synthetic division with the coefficients of \( f(x) = x^2 - x + 3 \). The coefficients are [1, -1, 3] and we will use the complex number \( 3 - 2i \) for division.
04
Perform synthetic division
1. Write down the coefficients: \[ 1, -1, 3 \]2. Bring down the first coefficient: 13. Multiply 1 by \( 3 - 2i \): \( 1 \times (3 - 2i) = 3 - 2i \)4. Add this value to the next coefficient: \( -1 + (3 - 2i) = 2 - 2i \)5. Multiply \( 2 - 2i \) by \( 3 - 2i \): \( (2 - 2i)(3 - 2i) = 6 - 4i - 6i + 4i^2 = 6 - 10i - 4 = 2 - 10i \)6. Add this result to the last coefficient: \( 3 + (2 - 10i) = 5 - 10i \)
05
Conclusion from synthetic division
The final remainder from the synthetic division is \( 5 - 10i \). According to the remainder theorem, \( f(3 - 2i) = 5 - 10i \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
synthetic division
Synthetic division is a simplified way to divide a polynomial by a binomial of the form \((x - k)\). It's much quicker and more straightforward than traditional long division, especially when performed with polynomials. We set up synthetic division by listing the coefficients of the polynomial and then follow a series of multiplication and addition steps to find the remainder. Here’s a simple way to understand it:
- Write down the coefficients of the polynomial in a row.
- Bring down the leading coefficient to start our calculations.
- Multiply it by \((k)\) and add this product to the next coefficient.
- Continue these steps until you’ve processed all coefficients.
polynomial functions
Polynomial functions are expressions involving a sum of powers in one or more variables multiplied by coefficients. For a single variable polynomial, it will look like: \[f(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0 \] where each \(a_i\) is a coefficient, and \(n\) is a non-negative integer. They can be of any degree, from a simple constant to a complex expression involving high powers of \(x\). In our exercise, the polynomial is \(f(x) = x^2 - x + 3\):
- The coefficients are [1, -1, 3].
- These represent the terms \(x^2\), \(-x\), and the constant 3, respectively.
complex numbers
Complex numbers expand the concept of numbers beyond the real numbers to include \(i\), an imaginary unit where \(i^2 = -1\). A complex number is typically written in the form \((a + bi)\) where \(a\) and \(b\) are real numbers. In our exercise, we dealt with \(3 - 2i\):
- The real part is 3.
- The imaginary part is -2i.