Chapter 1: Problem 43
Multiply the algebraic expressions using a Special Product Formula and simplify. $$(y+2)^{3}$$
Short Answer
Expert verified
\((y+2)^3 = y^3 + 6y^2 + 12y + 8\).
Step by step solution
01
Identify the Formula
Recognize that the expression \((y+2)^3\) is in the form of \((a + b)^3\). We can use the special product formula for cubes. The formula is \((a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\).
02
Substitute Values into Formula
Here, compare \(y + 2\) to \(a + b\). Thus, \(a = y\) and \(b = 2\). Substitute these values into the formula: \(a^3 + 3a^2b + 3ab^2 + b^3\).
03
Calculate Individual Terms
Calculate each term in the formula: 1. \(a^3 = y^3\) 2. \(3a^2b = 3(y^2)(2) = 6y^2\) 3. \(3ab^2 = 3(y)(2^2) = 12y\) 4. \(b^3 = 2^3 = 8\)
04
Combine the Terms
Add all the terms together: \(y^3 + 6y^2 + 12y + 8\). This is the simplified form of \((y+2)^3\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Algebraic Expressions
An algebraic expression is a combination of numbers, variables, and operations like addition and subtraction. It's a fundamental building block in mathematics and helps us describe and solve problems involving relationships between different quantities.
Algebraic expressions can include:
For instance, in polynomial expansions or operations involving special product formulas, recognizing the pattern of algebraic expressions allows for quicker solutions.
Algebraic expressions can include:
- Variables: Letters that represent unknown numbers, like \( x \) or \( y \).
- Constants: Numbers that are fixed, like \( 2 \) or \( -5 \).
- Operators: Symbols that show the operations to be performed, such as \( +, -, \times, \) or \( \div \).
For instance, in polynomial expansions or operations involving special product formulas, recognizing the pattern of algebraic expressions allows for quicker solutions.
Polynomial Expansion
Polynomial expansion involves expressing a polynomial raised to a power as a sum of terms. By using special formulas, such as the binomial theorem, we can expand expressions like \((y+2)^3\) into a longer polynomial format.
The special product formula used here is for cubes:
For example, in \((y+2)^3\), we substitute \(y\) for \(a\) and \(2\) for \(b\), and apply the formula by calculating each component:
Such expansions are foundational in algebra for simplifying complex expressions and solving polynomial equations effectively.
The special product formula used here is for cubes:
- \((a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\)
For example, in \((y+2)^3\), we substitute \(y\) for \(a\) and \(2\) for \(b\), and apply the formula by calculating each component:
- \(a^3 = y^3\)
- \(3a^2b = 3(y^2)(2) = 6y^2\)
- \(3ab^2 = 3(y)(2^2) = 12y\)
- \(b^3 = 2^3 = 8\)
Such expansions are foundational in algebra for simplifying complex expressions and solving polynomial equations effectively.
Cubic Binomials
Cubic binomials are expressions of the form \((a+b)^3\), involving two terms raised to the third power. Understanding cubic binomials allows students to perform polynomial expansions efficiently.
They appear often in algebraic problems, as they enable the transformation of a compact binomial form into a fuller, explicit polynomial, which can be helpful in identifying roots or in further manipulation.
The key to handling cubic binomials is the application of the special product formula for cubes:
They appear often in algebraic problems, as they enable the transformation of a compact binomial form into a fuller, explicit polynomial, which can be helpful in identifying roots or in further manipulation.
The key to handling cubic binomials is the application of the special product formula for cubes:
- \((a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\)
- Convert \(a^3\), \(3a^2b\), \(3ab^2\), and \(b^3\) into their components.
- Combine these to get \(y^3 + 6y^2 + 12y + 8\).