Chapter 9: Problem 21
Find the area of the parallelogram determined by the given vectors. $$\mathbf{u}=\langle 3,2,1\rangle, \quad \mathbf{v}=\langle 1,2,3\rangle$$
Short Answer
Expert verified
The area of the parallelogram is \( 4\sqrt{6} \).
Step by step solution
01
Understand the Formula
To find the area of a parallelogram formed by two vectors \( \mathbf{u} \) and \( \mathbf{v} \), we use the cross product. The area is given by the magnitude of the cross product of the two vectors, \( \| \mathbf{u} \times \mathbf{v} \| \).
02
Compute the Cross Product
Calculate the cross product \( \mathbf{u} \times \mathbf{v} \) using the formula:\[ \mathbf{u} \times \mathbf{v} = \left| \begin{array}{ccc} \mathbf{i} & \mathbf{j} & \mathbf{k} \ 3 & 2 & 1 \ 1 & 2 & 3 \end{array} \right| \]This determinant calculation involves:\[ \mathbf{u} \times \mathbf{v} = \mathbf{i}(2 \cdot 3 - 1 \cdot 2) - \mathbf{j}(3 \cdot 3 - 1 \cdot 1) + \mathbf{k}(3 \cdot 2 - 2 \cdot 1) \]Solve the determinants: \( = 4\mathbf{i} - 8\mathbf{j} + 4\mathbf{k} \).
03
Find the Magnitude of the Cross Product
The magnitude of the cross product \( \mathbf{u} \times \mathbf{v} \) represents the area of the parallelogram. Calculate:\[ \| \mathbf{u} \times \mathbf{v} \| = \sqrt{4^2 + (-8)^2 + 4^2} \]This simplifies to \( \sqrt{16 + 64 + 16} = \sqrt{96} \).
04
Simplify the Magnitude
Simplify the magnitude \( \sqrt{96} \) further to find the final area in the simplest form. \[ \sqrt{96} = \sqrt{16 \times 6} = 4 \sqrt{6} \]
05
Write the Final Answer
The area of the parallelogram formed by the vectors \( \mathbf{u} = \langle 3, 2, 1 \rangle \) and \( \mathbf{v} = \langle 1, 2, 3 \rangle \) is \( 4\sqrt{6} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
The cross product, also known as the vector product, is a mathematical operation that is used to find a vector perpendicular to two given vectors in three-dimensional space. This is key in vector calculus, as it allows us to calculate important geometric quantities such as the area of parallelograms.
- Given two vectors \( \mathbf{a} = \langle a_1, a_2, a_3 \rangle \) and \( \mathbf{b} = \langle b_1, b_2, b_3 \rangle \), their cross product \( \mathbf{a} \times \mathbf{b} \) is expressed as:
Parallelogram Area
The area of a parallelogram can be effortlessly computed in three-dimensional space using the cross product of two vectors that define the parallelogram. The formula used is:
Let's break it down:
- The area \( A \) is simply the magnitude of the cross product of the vectors:
Let's break it down:
- A larger cross product magnitude indicates a larger spanning area.
- The vectors \( \mathbf{u} \) and \( \mathbf{v} \) are seen as two sides meeting to form the parallelogram.
- This is analogous to a base-height calculation, but instead with vectors.
Determinant
The concept of a determinant arises when calculating the cross product using its determinant form. It's a compact way to encapsulate the necessary operations among the components of vectors in three-dimensional space.
- Determinants can be seen as a scale factor, providing area or volume under specific conditions.
- In the cross product calculation, the determinant helps evaluate the components of the resulting vector.