Chapter 3: Problem 67
Find all solutions of the equation and express them in the form \(a+b i.\) $$6 x^{2}+12 x+7=0$$
Short Answer
Expert verified
The solutions are \(-1 + \frac{\sqrt{6}}{6}i\) and \(-1 - \frac{\sqrt{6}}{6}i\).
Step by step solution
01
Identify the coefficients
The given quadratic equation is \(6x^2 + 12x + 7 = 0\). In this equation, the coefficients are identified as \(a = 6\), \(b = 12\), and \(c = 7\).
02
Calculate the discriminant
The discriminant \(D\) of a quadratic equation \(ax^2 + bx + c = 0\) is calculated using the formula \(D = b^2 - 4ac\). Substituting the given values, we have \(D = 12^2 - 4 \times 6 \times 7 = 144 - 168 = -24\).
03
Determine the nature of the roots
Since the discriminant \(D\) is negative \((-24)\), the equation has two complex roots. These roots will be in the form \(a + bi\).
04
Use the quadratic formula
The roots of the quadratic equation can be found using the quadratic formula: \[ x = \frac{-b \pm \sqrt{D}}{2a} \]. Substituting the values \(b = 12\), \(D = -24\), and \(a = 6\), we get: \[ x = \frac{-12 \pm \sqrt{-24}}{12} \].
05
Simplify the roots
Since the square root of a negative number involves an imaginary unit \(i\), we have \(\sqrt{-24} = \sqrt{24}i = 2\sqrt{6}i\). Substituting this back into the equation gives: \[ x = \frac{-12 \pm 2\sqrt{6}i}{12} \].
06
Separate the real and imaginary parts
Divide each term in the numerator by 12: \[ x = \frac{-12}{12} \pm \frac{2\sqrt{6}i}{12} = -1 \pm \frac{\sqrt{6}}{6}i \]. Thus, the solutions are \(-1 + \frac{\sqrt{6}}{6}i\) and \(-1 - \frac{\sqrt{6}}{6}i\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a powerful tool in solving quadratic equations. It helps us determine the nature of the roots without actually solving the equation. For a quadratic equation of the form \(ax^2 + bx + c = 0\), the discriminant \(D\) is calculated using the formula:\[D = b^2 - 4ac\]The value of the discriminant is crucial because:
- If \(D > 0\), there are two distinct real roots.
- If \(D = 0\), there is exactly one real root (or a repeated root).
- If \(D < 0\), there are two complex roots.
Complex Roots
Complex roots arise when the discriminant of a quadratic equation is negative. This means the expression under the square root in the quadratic formula results in a negative number, which leads to imaginary numbers in the solution. Remember, the imaginary unit \(i\) is defined as \(\sqrt{-1}\). Therefore, when we calculate \(\sqrt{-24}\), it becomes \(2\sqrt{6}i\). In our equation, we find the complex roots using:\[ x = \frac{-b \pm \sqrt{D}}{2a} \]Substituting the values, the expression becomes:\[ x = \frac{-12 \pm 2\sqrt{6}i}{12} \]Thus, the solutions \(-1 + \frac{\sqrt{6}}{6}i\) and \(-1 - \frac{\sqrt{6}}{6}i\) are complex because they include \(i\), which indicates the presence of an imaginary component. Each solution consists of a real part \(-1\) and an imaginary part \(\pm \frac{\sqrt{6}}{6}i\).
Quadratic Formula
The quadratic formula is an essential method for solving quadratic equations. It provides a straightforward way to find the roots by substituting values into a well-defined formula:\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]Here, \(b^2 - 4ac\) is known as the discriminant. This formula can solve any quadratic equation, provided \(a\), \(b\), and \(c\) are known.For the quadratic equation \(6x^2 + 12x + 7 = 0\), plugging in \(a = 6\), \(b = 12\), and \(c = 7\) into the quadratic formula gives:\[x = \frac{-12 \pm \sqrt{-24}}{12}\]Since \(\sqrt{-24}\) involves an imaginary number, the roots are complex.Follow these steps:
- Calculate \(\sqrt{-24} = 2\sqrt{6}i\).
- Substitute back to simplify further: \(x = \frac{-12 \pm 2\sqrt{6}i}{12}\).
- Separate into real and imaginary parts, yielding our complex solutions: \(-1 + \frac{\sqrt{6}}{6}i\) and \(-1 - \frac{\sqrt{6}}{6}i\).