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91Ó°ÊÓ

Find the intercepts and asymptotes, and then sketch a graph of the rational function. Use a graphing device to confirm your answer. $$t(x)=\frac{3 x+6}{x^{2}+2 x-8}$$

Short Answer

Expert verified
x-intercept: (-2, 0), y-intercept: (0, -3/4); Vertical asymptotes: x = 2, x = -4; Horizontal asymptote: y = 0.

Step by step solution

01

Find the x-intercepts

To find the \(x\)-intercepts of the function \(t(x) = \frac{3x + 6}{x^2 + 2x - 8}\), we set the numerator equal to zero: \[ 3x + 6 = 0 \] Solving for \(x\), we get \[ x = -2 \] Therefore, the \(x\)-intercept is \((-2, 0)\).
02

Find the y-intercept

To find the \(y\)-intercept, set \(x = 0\) in the function \(t(x)\):\[ t(0) = \frac{3(0) + 6}{0^2 + 2(0) - 8} = \frac{6}{-8} = -\frac{3}{4} \]Thus, the \(y\)-intercept is \((0, -\frac{3}{4})\).
03

Factor the denominator for vertical asymptotes

We need to factor the denominator \(x^2 + 2x - 8\) to find vertical asymptotes. Factoring gives us:\[ x^2 + 2x - 8 = (x - 2)(x + 4) \]Setting each factor of the denominator equal to zero, we get possible vertical asymptotes at \(x = 2\) and \(x = -4\).
04

Determine horizontal asymptote

For the rational function \(t(x) = \frac{3x + 6}{x^2 + 2x - 8}\), the degree of the numerator (1) is less than the degree of the denominator (2). This means the horizontal asymptote is at \(y = 0\).
05

Sketch the graph

Plot the intercepts \((-2, 0)\) and \((0, -\frac{3}{4})\). Draw vertical asymptotes at \(x = 2\) and \(x = -4\), and a horizontal asymptote at \(y = 0\). The graph will approach but never cross the vertical asymptotes, and as \(x\) goes to infinity or negative infinity, the graph will approach \(y = 0\). Confirm this sketch using a graphing device.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intercepts
Intercepts in a rational function are points where the graph crosses the axes. This includes the x-intercept and y-intercept. To find the x-intercept of the function \( t(x) = \frac{3x + 6}{x^2 + 2x - 8} \), you set the numerator equal to zero because the fraction only equals zero when its numerator is zero. Solve \( 3x + 6 = 0 \) to find \( x = -2 \). This tells us the x-intercept is \( (-2, 0) \).

For the y-intercept, set \( x = 0 \) in the function. This means calculating \( t(0) = \frac{3(0) + 6}{0^2 + 2(0) - 8} = -\frac{3}{4} \). Hence, the y-intercept is at \( (0, -\frac{3}{4}) \). These points are useful for sketching the initial path of the graph.
Asymptotes
Asymptotes are lines that a graph approaches but never actually touches. There are two types to find for rational functions: vertical and horizontal asymptotes.

Vertical asymptotes occur where the denominator is zero, so factor the denominator \( x^2 + 2x - 8 \) to \( (x - 2)(x + 4) \). Set each factor to zero: \( x - 2 = 0 \) and \( x + 4 = 0 \) give \( x = 2 \) and \( x = -4 \) as vertical asymptotes.

To find horizontal asymptotes, compare the degrees of the numerator and the denominator. Here, the numerator has degree 1 and the denominator has degree 2. Since the numerator's degree is less, the horizontal asymptote is \( y = 0 \). The graph will get very close to these lines but will not touch them.
Graphing
Graphing a rational function like \( t(x) = \frac{3x + 6}{x^2 + 2x - 8} \) requires plotting intercepts and asymptotes. Start by marking the x-intercept \((-2, 0)\) and y-intercept \((0, -\frac{3}{4})\).

Draw vertical dashed lines at \( x = 2 \) and \( x = -4 \) to represent the vertical asymptotes, and a horizontal dashed line along \( y = 0 \) as the horizontal asymptote.

Sketch the curve such that it approaches these asymptotes, but never crosses them. Near vertical asymptotes, the graph will rise or fall sharply. As \( x \) moves towards positive or negative infinity, the graph will flatten out towards \( y = 0 \). Finally, confirm your sketch with a graphing device to ensure accuracy. This process helps visualize how the rational function behaves, providing insights into its behavior across different values of \( x \).

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