/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Sketch the graph of the function... [FREE SOLUTION] | 91Ó°ÊÓ

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Sketch the graph of the function by first making a table of values. \(f(x)=\frac{x}{|x|}\)

Short Answer

Expert verified
The function graph consists of two horizontal lines: one on \(y = -1\) for \(x < 0\) and the other on \(y = 1\) for \(x > 0\), with a discontinuity at \(x = 0\).

Step by step solution

01

Understand the piecewise function

Given the piecewise function \(f(x) = \frac{x}{|x|}\), we need to analyze it for different values of \(x\). The absolute value \(|x|\) ensures \(f(x) = 1\) if \(x > 0\) and \(f(x) = -1\) if \(x < 0\). Define \(f(x)\) as undefined for \(x = 0\).
02

Create a table of values

Choose a set of values for \(x\) to substitute into the function. Since \(f(x)\) is only defined for \(x eq 0\), we choose \(x = -2, -1, -0.5, 0.5, 1, 2\). Fill the table with corresponding \(f(x)\) values: \[\begin{array}{c|c}x & f(x) \\hline-2 & -1 \-1 & -1 \-0.5 & -1 \0.5 & 1 \1 & 1 \2 & 1 \\end{array}\]
03

Plot the points on a graph

Using the table, plot the points \((-2, -1), (-1, -1), (-0.5, -1)\) on the y = -1 line and \((0.5, 1), (1, 1), (2, 1)\) on the y = 1 line. These points show the discontinuity at \(x = 0\).
04

Draw the graph

Since the function shifts from \(-1\) to \(1\) at \(x = 0\), we draw two horizontal lines: one on \(y=-1\) for \(x < 0\) and the other on \(y = 1\) for \(x > 0\). The graph is discontinuous at \(x = 0\), where \(f(x)\) is undefined.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absolute Value Functions
Absolute value functions are a unique type of function where the output is always non-negative, regardless of whether the input (or the expression within the absolute value) is negative or positive. An absolute value function is typically written as \(y = |x|\), and it represents the distance from zero on the number line. This makes it an essential concept when graphing functions that involve absolute values since it directly affects the behavior or direction of the graph.
  • For positive numbers, \( |x| = x \).
  • For negative numbers, \( |x| = -x \).

  • In the given exercise, the absolute value function \( |x| \) is in the denominator of the expression \(f(x) = \frac{x}{|x|}\). This modifies the function into a piecewise-defined function because the behavior changes from positive to negative depending on the sign of \(x\). For of values \(x > 0\), the function evaluates to 1, as \(x\) and \(|x|\) cancel each other out. Conversely, for \(x < 0\), the result is -1. This clear switch is due to the properties of absolute value functions.
    Discontinuity
    Discontinuity in a function occurs when there is a sudden jump or break in the graph. In mathematical terms, a point of discontinuity is a specific value of \(x\) where the function does not have a well-defined single value. A very clear example of discontinuity is shown in the function \(f(x) = \frac{x}{|x|}\), as detailed in the original exercise. Here, there is a break at \(x = 0\) where the function is undefined.
  • At \(x=0\), the absolute value makes the denominator zero, resulting in the function being undefinable at this point.

  • This point of undefined value means that you cannot draw the graph of the function smoothly through \(x = 0\). Discontinuities are important because they show where functions might behave unexpectedly, and it's crucial to recognize these points when analyzing or sketching graphs.
    Graphing Functions
    Graphing functions involves creating a visual representation of a function's behavior across different values of \(x\). It requires plotting points from a table of values, which enables a deeper understanding of how functions behave. In the original exercise, you're dealing with the function \(f(x) = \frac{x}{|x|}\).
  • Points were calculated and plotted for \(x\) values such as -2, -1, -0.5, 0.5, 1, and 2.
  • For values \(x > 0\), the points lie along the line \(y = 1\). For values \(x < 0\), the points lie along the line \(y = -1\).

  • The discontinuity at \(x = 0\) presents itself as a gap in the graph, illustrating that the function does not have a defined value at this point. By understanding these concepts, it becomes easier to predict the general shape and key characteristics of functions not only in simple exercises, but also in complex mathematical applications.

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    Most popular questions from this chapter

    In the margin notes in this section we pointed out that the inverse of a function can be found by simply reversing the operations that make up the function. For instance, in Example 6 we saw that the inverse of $$f(x)=3 x-2 \quad \text { is } \quad f^{-1}(x)=\frac{x+2}{3}$$ because the "reverse" of "multiply by 3 and subtract 2" is "add 2 and divide by 3 " Use the same procedure to find the inverse of the following functions. (a) \(f(x)=\frac{2 x+1}{5}\) (b) \(f(x)=3-\frac{1}{x}\) (c) \(f(x)=\sqrt{x^{3}+2}\) (d) \(f(x)=(2 x-5)^{3}\) Now consider another function: \(f(x)=x^{3}+2 x+6\) Is it possible to use the same sort of simple reversal of operations to find the inverse of this function? If so, do it. If not, explain what is different about this function that makes this task difficult.

    Changing Temperature Scales The temperature on a certain afternoon is modeled by the function $$C(t)=\frac{1}{2} t^{2}+2$$ where \(t\) represents hours after 12 noon \((0 \leq t \leq 6),\) and \(C\) is measured in "C. (a) What shifting and shrinking operations must be performed on the function \(y=t^{2}\) to obtain the function \(y=C(t) ?\) (b) Suppose you want to measure the temperature in "F instead. What transformation would you have to apply to the function \(y=C(t)\) to accomplish this? (Use the fact that the relationship between Celsius and Fahrenheit degrees is given by \(F=\frac{9}{5} C+32 .\) ) Write the new function \(y=F(t)\) that results from this transformation.

    The graphs of \(f(x)=x^{2}-4\) and \(g(x)=\left|x^{2}-4\right|\) are shown. Explain how the graph of \(g\) is obtained from the graph of \(f\) (Graph can't copy)

    In a certain state the maximum speed permitted on freeways is \(65 \mathrm{mi} / \mathrm{h}\) and the minimum is \(40 .\) The fine \(F\) for violating these limits is \(\$ 15\) for every mile above the maximum or below the minimum. (a) Complete the expressions in the following piecewise defined function, where \(x\) is the speed at which you are driving. $$F(x)=\left\\{\begin{array}{ll}\text {\(\text{________ }\) if } 0 < x < 40 \\\\\text {\(\text{________ }\) if } 40 \leq x \leq 65 \\\\\text {\(\text{________ }\) if } x > 65\end{array}\right.$$ (b) Find \(F(30), F(50),\) and \(F(75)\). (c) What do your answers in part (b) represent?

    Area of a Ripple A stone is dropped in a lake, creating a circular ripple that travels outward at a speed of \(60 \mathrm{cm} / \mathrm{s}\). (a) Find a function \(g\) that models the radius as a function of time. (b) Find a function \(f\) that models the area of the circle as a function of the radius. (c) Find \(f \circ g .\) What does this function represent?

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