/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Use a system of equations to fin... [FREE SOLUTION] | 91影视

91影视

Use a system of equations to find the parabola of the form \(y=a x^{2}+b x+c\) that goes through the three given points. $$(0,0),(1,3),(2,2)$$

Short Answer

Expert verified
The equation of the parabola is \(y = -2x^2 + 5x\).

Step by step solution

01

Set Up the Equations

Use the general form of a parabola, \(y = ax^2 + bx + c\). Substitute each given point into the equation to create a system of three equations. For point \((0,0)\): \(0 = a(0)^2 + b(0) + c\), which simplifies to \(c = 0\). For point \((1,3)\): \(3 = a(1)^2 + b(1) + c\), which simplifies to \(3 = a + b + c\). For point \((2,2)\): \(2 = a(2)^2 + b(2) + c\), which simplifies to \(2 = 4a + 2b + c\).
02

Substitute Known Values

From Step 1, we know \(c = 0\). Substitute \(c = 0\) into the remaining equations: \(3 = a + b\) and \(2 = 4a + 2b\).
03

Solve the System of Equations

We now have two equations with two variables: \(3 = a + b\) and \(2 = 4a + 2b\). Solve the first equation for one variable: \(b = 3 - a\). Substitute this into the second equation: \(2 = 4a + 2(3 - a)\). Simplify and solve for \(a\): \(2 = 4a + 6 - 2a\) or \(2 = 2a + 6\) or \(-4 = 2a\) or \(a = -2\).
04

Find Remaining Variable

Substitute \(a = -2\) back into \(b = 3 - a\): \(b = 3 - (-2)\) or \(b = 5\).
05

Write the Parabola Equation

Combine the values of \(a\), \(b\), and \(c\) into the general form \(y = ax^2 + bx + c\). Therefore, the equation of the parabola is \(y = -2x^2 + 5x\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

parabola
A parabola is a U-shaped curve that can open upwards or downwards. It is the graph of a quadratic function. The most basic form of a parabola opens upwards and is symmetrical around a vertical axis of symmetry. When graphed on a coordinate plane, it generally looks like a bowl or a hill, depending on its concavity.

Parabolas have several key features:
  • **Vertex**: The highest or lowest point of the parabola, also the point where the axis of symmetry intersects the parabola.
  • **Axis of Symmetry**: The vertical line that splits the parabola into two mirror-image halves.
  • **Focus and Directrix**: Geometric traits used to define the parabola. The distance from any point on the parabola to the focus equals the distance from that point to the directrix.
A parabola can be represented by the equation: \(y = ax^2 + bx + c\) where 'a', 'b', and 'c' are coefficients. Key changes occur when manipulating these coefficients. For instance:
  • If 'a' is positive, the parabola opens upwards.
  • If 'a' is negative, it opens downwards.
  • The values of 'b' and 'c' affect the position of the vertex and the parabola's intersection with the y-axis.
quadratic functions
Quadratic functions are fundamental in algebra and feature prominently in many real-life scenarios. They can be used to model phenomena such as projectile motion, profit maximization in business, and many more. The standard form of a quadratic function is: \(y = ax^2 + bx + c\)

Let's delve into the details:
  • **Coefficient 'a'**: Determines the
systems of linear equations
To find the equation of a parabola passing through three points, we must use systems of linear equations. This might sound complicated, but it's manageable with a few steps.

Any quadratic function can be expressed as: \(y = ax^2 + bx + c\).
Suppose you have three points given, say \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\). To find the quadratic equation, substitute these points into the quadratic function:
  • For \((x_1, y_1)\): \(y_1 = a x_1^2 + b x_1 + c\).
, 屑芯蟹写薪褘泄; 写胁褍褏side 褌褉械褍谐芯谢褜薪褘泄;plasirections 褌芯褔薪芯褋褌褜 褎oco 胁芯胁械褉褌 fixes 写胁褍褏胁械褌褉懈褟;转谢邪谐 Alth写 懈蟹薪邪薪芯屑 谢懈}} 懈褋褏芯写褗褞 写谢褟< li>board empregado 蟹邪写褉懈-proclare nieto 写谢褟 points 芯写薪芯屑}} his 写谢褟 写芯褋械谢褜.) 蟹薪邪薪懈械 褌褉芯泻芯谐 prove 写谢褟.)邪斜芯胁 褝褌芯 写谢褟}} 写谢褟al 写芯锌芯谢 ell袙褘 sev 锌谢邪褌械卸escription 褌芯褔泻懈 芯写薪懈屑 que 褉械谐褍谢懈 褌芯褔械泻 写谢褟: reguldid
  • 褌芯褔械泻}} 写谢褟 褌芯褔械泻 写谢褟 褌芯褔泻懈 褌芯褔械 写谢褟 胁邪谢褞褌褍 写谢褟 锌芯cale`). up 谢懈 芯褎褎械褉械褋褋褍褞褖械泄
  • ).

    One App. One Place for Learning.

    All the tools & learning materials you need for study success - in one app.

    Get started for free

    Most popular questions from this chapter

    See all solutions

    Recommended explanations on Math Textbooks

    View all explanations

    What do you think about this solution?

    We value your feedback to improve our textbook solutions.

    Study anywhere. Anytime. Across all devices.