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Find each partial fraction decomposition. $$\frac{9 x^{2}+21 x-24}{x^{3}+4 x^{2}-11 x-30}$$

Short Answer

Expert verified
\[\frac{9x^2 + 21x - 24}{x^3 + 4x^2 - 11x - 30} = \frac{1}{x+2} + \frac{2}{x-3} + \frac{6}{x+5}\]

Step by step solution

01

Factor the Denominator

Factor the denominator polynomial. Given: \[x^3 + 4x^2 - 11x -30 = (x+2)(x-3)(x+5)\]The denominator factors into three linear factors.
02

Set Up Partial Fractions

Express the rational function as a sum of partial fractions: \[\frac{9x^2 + 21x - 24}{x^3 + 4x^2 - 11x - 30} = \frac{A}{x+2} + \frac{B}{x-3} + \frac{C}{x+5}\]where A, B, and C are constants to be determined.
03

Clear the Denominator

Multiply both sides by the common denominator \[(x+2)(x-3)(x+5)\] to clear the fractions:\[9x^2 + 21x - 24 = A(x-3)(x+5) + B(x+2)(x+5) + C(x+2)(x-3)\]
04

Expand and Collect Like Terms

Expand the right-hand side and collect like terms to form an equation in terms of x:\[9x^2 + 21x - 24 = A(x^2 + 2x - 15) + B(x^2 + 7x + 10) + C(x^2 - x - 6)\]Combine like terms:\[9x^2 + 21x - 24 = (A+B+C)x^2 + (2A+7B-C)x + (-15A + 10B - 6C)\]
05

Set Up and Solve the System of Equations

Set up the system of equations by equating the coefficients from both sides:1. \(A + B + C = 9\) 2. \(2A + 7B - C = 21\) 3. \(-15A + 10B - 6C = -24\)Solve this system to find A, B, and C.
06

Solve for A, B, and C

Solving the system of equations, we get:\(A = 1\), \(B = 2\), and \(C = 6\).
07

Write the Partial Fraction Decomposition

Substitute the values of A, B, and C back into the partial fraction expression:\[\frac{9x^2 + 21x - 24}{x^3 + 4x^2 - 11x - 30} = \frac{1}{x+2} + \frac{2}{x-3} + \frac{6}{x+5}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rational Functions
A rational function is a fraction where both the numerator and the denominator are polynomials. An example is the function in our exercise: \(\frac{9x^2 + 21x - 24}{x^3 + 4x^2 - 11x - 30}\). These functions are essential in mathematics because they often appear in real-world applications, such as physics and engineering.
To understand a rational function better, we can decompose it into simpler fractions, which makes it easier to analyze and integrate. This process is called partial fraction decomposition. By breaking down a complex rational function into simpler parts, we can solve integrals, differential equations, and other mathematical problems more easily.
System of Equations
To find constants in partial fraction decomposition, we often need to solve a system of equations. Systems of equations are sets of equations with multiple variables that we solve simultaneously. In our example:
\(\begin{align*} A + B + C &= 9,\ 2A + 7B - C &= 21,\ -15A + 10B - 6C &= -24 \end{align*}\)
We found three equations derived from comparing coefficients of like terms.
Solving systems can be done with methods like substitution, elimination, or using matrices. In this case, solving reveals that \(A = 1\), \(B = 2\), and \(C = 6\). Once we have these values, we substitute them back into the partial fractions to reconstruct the original rational function.
Polynomial Factorization
Factorization simplifies polynomials into products of simpler polynomials, which is crucial for partial fraction decomposition. For example, the denominator polynomial \((x^3 + 4x^2 - 11x - 30)\) can be factored as \( (x+2)(x-3)(x+5)\). These factors break the polynomial into linear components.
Factoring polynomials involves finding the roots or zeros of the polynomial, which are values of x where the polynomial equals zero. Techniques include synthetic division, long division, and using the quadratic formula for quadratic polynomials.
By factoring the denominator, we express complicated fractions in simpler forms, paving the way to solving for constants in partial fraction decomposition.

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