/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Find the indicated value of the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indicated value of the logarithmic functions. $$\log _{1 / 5}(125)$$

Short Answer

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Step by step solution

01

Understand the Logarithmic Form

Recall that \(\text{if } \log_b(a) = c, \text{ then } b^c = a\). In this problem, we need to find \(\log_{1/5}(125)\). This implies \(\left(\frac{1}{5}\right)^c = 125\).
02

Rewrite the Base and Argument

Rewrite the fraction \(\frac{1}{5}\) as \(5^{-1}\). So the equation becomes \(\left(5^{-1}\right)^c = 125\). Simplify the left side: \(5^{-c} = 125\).
03

Express 125 as a Power of 5

Determine the power of 5 that equals 125: \(125 = 5^3\). Therefore, the equation now is \(5^{-c} = 5^3\).
04

Set the Exponents Equal

Since the bases are the same, set the exponents equal to each other: \(-c = 3\).
05

Solve for c

Solve the equation for \(c\) by multiplying both sides by \(-1\): \c = -3\.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithms
Logarithms are the inverse operation to exponentiation. They help us solve for the unknown exponent in an equation of the form \(b^c = a\). Here, \log_b(a) = c\ indicates that \(b\) raised to the power \(c\) equals \(a\). Understanding logarithms is essential because they transform multiplicative processes into additive ones, making complex computations more manageable. For example, in the given problem, you need to identify the value of the logarithmic function \log_{1/5}(125)\ by converting it into an equation involving exponentiation.
Exponentiation
Exponentiation is a mathematical operation where a number (the base) is raised to a certain power (the exponent). For example, \(5^3 = 125\). This operation is the fundamental process reversed by logarithms. In the context of the problem \log_{1/5}(125)\, converting the logarithm to its exponential form helps in solving it. \left(\frac{1}{5}\right)^c = 125\. This reveals that we are trying to find an exponent \(c\) such that \(\frac{1}{5}\) raised to that power equals 125.
Base Conversion
Base conversion involves changing the representation of a number from one base to another. For instance, converting the base \( \frac{1}{5} \) to \5^{-1}\ is a crucial step in solving the given problem. By rewriting \left(\frac{1}{5}\right)^c\ as \left(5^{-1}\right)^c\, it simplifies to \5^{-c}\. This makes it straightforward to compare the exponents once the bases match. Hence, understanding base conversion allows us to handle and manipulate complex expressions with ease.
Solving Equations
Solving logarithmic equations often involves converting them to an exponential form and then isolating the unknown variable. For \log_{1/5}(125)\, following these steps simplifies the process:
  • Rewrite \frac{1}{5}\ as \5^{-1}\ to obtain \5^{-c} = 125\.
  • Then, express 125 as \( 5^3 \).
With the same base on both sides, you can set the exponents equal to each other: \-c = 3\.
Finally, solving for \c\ by multiplying both sides by \-1\ yields \c = -3\. These steps show how converting forms and isolating variables help solve logarithmic problems effectively.

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