/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 112 Solve each equation. Find the ex... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve each equation. Find the exact solutions. $$\log _{2}\left(\log _{2}\left(\log _{2}\left(2^{\left(4^{\circ}\right)}\right)\right)\right)=3$$

Short Answer

Expert verified
The exact solutions to the equation is \(\text{log}_{2}(\text{log}_{2}(\text{log}_{2}(2^{4^{\frac{4}{3}}}))) = 3\).

Step by step solution

01

Understand the given equation

The given equation is \(\text{log}_{2}(\text{log}_{2}(\text{log}_{2}(2^{4^{\frac{4}{3}}}))) = 3\). We need to solve for the variable (if present) or simplify the expression to meet the requirement of the equation.
02

Simplify the innermost logarithm

We start with the innermost expression, \(\text{log}_{2}(2^{4^{\frac{4}{3}}})\). Using the property of logarithms, \(\text{log}_b(a^c) = c \text{log}_b(a)\), we have: \(\text{log}_{2}(2^{4^{\frac{4}{3}}}) = 4^{\frac{4}{3}}\).
03

Simplify the next logarithm

Next, we simplify \(\text{log}_{2}(4^{\frac{4}{3}})\). Note that \(\text{log}_{2}(2^{2}) = 2\). So, \(\text{log}_{2}(4^{\frac{4}{3}}) = \text{log}_{2}((2^2)^{\frac{4}{3}}) = \text{log}_{2}(2^{\frac{8}{3}})\). Using the same property as above, we get: \(\frac{8}{3}\).
04

Simplify the outermost logarithm

Finally, we need to simplify \(\text{log}_{2}(\frac{8}{3})\). We know that \(\frac{8}{3} = 2^{3 - 1.415}\). Thus, \(\text{log}_{2}(2^{3 - 1.415}) = 3 - 1.415\). Simplifying further, we get \(\text{log}_{2}(4) = 3\).
05

Confirm the solution

From step 4, we found that \(\frac{8}{3} = 3\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

properties of logarithms
Logarithms follow several key properties that are essential for simplifying expressions and solving equations. One primary property is the product rule: \[\text{log}_b(mn) = \text{log}_b(m) + \text{log}_b(n)\]. This property allows you to split logarithms of products into simpler terms. The quotient rule is another vital property: \[\text{log}_b\frac{m}{n} = \text{log}_b(m) - \text{log}_b(n)\]. It helps to deal with logarithms of fractions by breaking them down into individual logs. One particularly useful property in solving equations is the power rule: \[\text{log}_b(m^n) = n \text{log}_b(m)\]. This rule enables you to move the exponent in the argument out as a multiplicative factor, making the expression easier to handle.
logarithmic simplification
Simplifying logarithmic expressions often involves using the properties of logarithms to transform complex expressions into simpler forms. For instance, in the given problem, we used the power rule extensively. The innermost logarithm, \(\text{log}_2(2^{4^{\frac{4}{3}}})\), simplifies to \(4^{\frac{4}{3}}\) because the base of the logarithm and the argument are the same. Then, we apply the power rule again when simplifying \(\text{log}_2(4^{\frac{4}{3}})\). Recognizing that \(4 = 2^2\), we rewrite the expression to apply the power rule: \(4^{\frac{4}{3}} = (2^2)^{\frac{4}{3}} = 2^{\frac{8}{3}}\). Hence, \(\text{log}_2(2^{\frac{8}{3}})\) becomes \(\frac{8}{3}\).
nested logarithms
Nested logarithms are logarithmic expressions within other logarithms, like \(\text{log}_a(\text{log}_b(x))\). Solving these requires working from the inside out. First, simplify the innermost logarithm before moving to the next. In our problem, we had multiple layers: \(\text{log}_{2}(\text{log}_{2}(\text{log}_{2}(2^{4^{\frac{4}{3}}})))\). We started by simplifying the innermost expression, \(\text{log}_{2}(2^{4^{\frac{4}{3}}})\), to get \(4^{\frac{4}{3}}\). Then we moved to the next layer: \(\text{log}_{2}(4^{\frac{4}{3}})\) and further reduced it to \(\text{log}_{2}(2^{\frac{8}{3}}) = \frac{8}{3}\). The final step involved simplifying the outermost logarithm using properties or other techniques.
change of base formula
The change of base formula is incredibly useful when dealing with logarithms, especially if the base is not convenient to work with. The formula is: \(\text{log}_b(a) = \frac{\text{log}_c(a)}{\text{log}_c(b)}\), where \(c\) is a new base, often chosen as 10 or \(e\). This formula helps convert logarithms from one base to another, simplifying calculations, especially on calculators that typically only allow log base 10 or natural log (base \(e\)). Although this formula wasn't directly used in our problem, it's vital to understand as it could be required in similar contexts. For our nested logarithms problem, knowing this could offer alternative ways to simplify the steps or verify results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve each problem. When needed, use 365 days per year and 30 days per month. Present Value Compounding Continuously Peoples Bank offers \(5.42 \%\) compounded continuously on CDs. What amount invested now would grow to \(\$ 20,000\) in 30 years. Hint Solve the continuous compounding formula for \(P\).

Use the following definition. In chemistry, the \(\mathrm{pH}\) of a solution is defined to be $$\mathrm{pH}=-\log \left[H^{+}\right],$$ where \(H^{+}\) is the hydrogen ion concentration of the solution in moles per liter. Distilled water has a pH of approximately 7. A substance with a pH under 7 is called an acid, and one with a pH over 7 is called a base. The hydrogen ion concentration of orange juice is \(10^{-3.7}\) moles per liter. Find the pH of orange juice.

Solve \(2^{x-3}=4^{5 x-1}\).

Consider the function \(y=\log \left(10^{n} \cdot x\right)\) where \(n\) is an integer. Use a graphing calculator to graph this function for several choices of \(n .\) Make a conjecture about the relationship between the graph of \(y=\log \left(10^{n} \cdot x\right)\) and the graph of \(y=\log (x) .\) Save your conjecture and attempt to prove it after you have studied the properties of logarithms, which are coming in Section \(4.3 .\) Repeat this exercise with \(y=\log \left(x^{n}\right)\) where \(n\) is an integer.

Cost of a Parking Ticket The cost of a parking ticket on campus is \(\$ 15\) for the first offense. Given that the cost doubles for each additional offense, write a formula for the cost C as a function of the number of tickets \(n\) First write some ordered pairs starting with \((1,15)\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.