Chapter 9: Problem 28
Use the binomial theorem to expand and simplify. $$\left(\frac{1}{2} x+y^{3}\right)^{4}$$
Short Answer
Expert verified
\(\left(\frac{1}{2}x + y^3\right)^4 = \frac{1}{16}x^4 + \frac{1}{2}x^3y^3 + \frac{3}{2}x^2y^6 + 2xy^9 + y^{12}\).
Step by step solution
01
Identify the Binomial Formula
The binomial theorem states that \[(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\]. In this exercise, the binomial expression is \((\frac{1}{2}x + y^3)^4\), where \(a = \frac{1}{2}x\), \(b = y^3\), and \(n = 4\).
02
Calculate Binomial Coefficients
The binomial coefficients are defined as \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \). For \( n = 4 \), the coefficients are:- \( \binom{4}{0} = 1 \)- \( \binom{4}{1} = 4 \)- \( \binom{4}{2} = 6 \)- \( \binom{4}{3} = 4 \)- \( \binom{4}{4} = 1 \)
03
Write and Simplify Each Term
Using the binomial theorem, expand each term separately:- For \( k = 0 \): \(\binom{4}{0}(\frac{1}{2}x)^{4-0}(y^3)^{0} = 1 \cdot (\frac{1}{2}x)^4 = \frac{1}{16}x^4\)- For \( k = 1 \): \(\binom{4}{1}(\frac{1}{2}x)^{4-1}(y^3)^{1} = 4 \cdot (\frac{1}{2}x)^3 \cdot y^3 = \frac{1}{2}x^3y^3\)- For \( k = 2 \): \(\binom{4}{2}(\frac{1}{2}x)^{4-2}(y^3)^{2} = 6 \cdot (\frac{1}{2}x)^2 \cdot y^6 = \frac{3}{2}x^2y^6\)- For \( k = 3 \): \(\binom{4}{3}(\frac{1}{2}x)^{4-3}(y^3)^{3} = 4 \cdot (\frac{1}{2}x) \, y^9 = 2xy^9\)- For \( k = 4 \): \(\binom{4}{4}(\frac{1}{2}x)^{4-4}(y^3)^{4} = 1 \cdot y^{12} = y^{12}\)
04
Combine All Terms
Combine the results from Step 3 to arrive at the final expanded form of the expression:\[ \left(\frac{1}{2}x + y^3\right)^4 = \frac{1}{16}x^4 + \frac{1}{2}x^3y^3 + \frac{3}{2}x^2y^6 + 2xy^9 + y^{12} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
Binomial coefficients play a crucial role in expanding expressions using the binomial theorem. These coefficients come from the patterns in expanding binomials, like \[ (a + b)^n \]. Each coefficient can be found using the formula: \[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \], where \( n! \) ("n factorial") is the product of all positive integers up to \( n \).
To better understand, consider the binomial expression \((a + b)^4\). The coefficients for this expansion are determined as follows:
To better understand, consider the binomial expression \((a + b)^4\). The coefficients for this expansion are determined as follows:
- \( \binom{4}{0} = 1 \)
- \( \binom{4}{1} = 4 \)
- \( \binom{4}{2} = 6 \)
- \( \binom{4}{3} = 4 \)
- \( \binom{4}{4} = 1 \)
Polynomial Expansion
Polynomial expansion involves expressing a binomial raised to a power as a polynomial. This is achieved using the binomial theorem, which breaks down the expression \( (a + b)^n \) into a sum of \( n+1 \) terms. Each term follows the pattern \( \binom{n}{k} a^{n-k} b^k \).
For example, the expression \((\frac{1}{2}x + y^3)^4\) can be expanded into a polynomial by following these steps:
For example, the expression \((\frac{1}{2}x + y^3)^4\) can be expanded into a polynomial by following these steps:
- Identify the values of \( a \), \( b \), and \( n \).
- Calculate the binomial coefficients for each \( k \) from \( 0 \) to \( n \).
- Use each coefficient to write the corresponding term.
- Simplify each term if needed, applying powers and distributing any constants.
Pascal's Triangle
Pascal's Triangle is a fascinating and practical tool for finding binomial coefficients quickly. Each row in the triangle corresponds to the coefficients for expanding \( (a + b)^n \). You start with a simple '1' at the top (the zeroth row).
Each subsequent number in the triangle is the sum of the two numbers directly above it in the previous row.
Here's a look at some starting rows of Pascal's Triangle:
Each subsequent number in the triangle is the sum of the two numbers directly above it in the previous row.
Here's a look at some starting rows of Pascal's Triangle:
- Row 0: 1
- Row 1: 1, 1
- Row 2: 1, 2, 1
- Row 3: 1, 3, 3, 1
- Row 4: 1, 4, 6, 4, 1