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Express in terms of logarithms of \(x, y, z\) or \(w\). (a) \(\log _{4}(x z)\) (b) \(\log _{4}(y / x)\) (c) \(\log _{4} \sqrt[3]{z}\)

Short Answer

Expert verified
(a) \( \log_{4}x + \log_{4}z \); (b) \( \log_{4}y - \log_{4}x \); (c) \( \frac{1}{3} \log_{4}z \)."

Step by step solution

01

Apply the Product Rule for Logarithms

The product rule states that \( \log_b(MN) = \log_b M + \log_b N \). For the expression \( \log_{4}(xz) \), we use this rule to separate the terms: \( \log_{4}(xz) = \log_{4}x + \log_{4}z \).
02

Apply the Quotient Rule for Logarithms

The quotient rule states that \( \log_b(\frac{M}{N}) = \log_b M - \log_b N \). For the expression \( \log_{4}(\frac{y}{x}) \), apply the rule: \( \log_{4}(y/x) = \log_{4}y - \log_{4}x \).
03

Apply the Power Rule for Logarithms

The power rule states that \( \log_b(M^k) = k \cdot \log_b M \). For the expression \( \log_{4} \sqrt[3]{z} \), note that \( \sqrt[3]{z} = z^{1/3} \). Applying the power rule gives: \( \log_{4}\sqrt[3]{z} = \frac{1}{3} \times \log_{4}z \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Product Rule for Logarithms
When working with logarithms, the product rule simplifies the logarithm of a product into the sum of separate logarithms. If you understand the basics of multiplication, you’ll find this rule intuitive. Consider the expression \( \log_{b}(MN) \). According to the product rule, this expression can be rewritten as \( \log_{b}M + \log_{b}N \). Essentially, multiplying two numbers and then taking the logarithm is the same as adding the logarithms of the individual numbers. This can make complex expressions easier to handle and helps in solving logarithmic equations.
  • The rule is helpful for expanding logarithmic expressions.
  • Useful for simplifying calculations in algebraic equations.
As applied in the exercise expression \( \log_{4}(xz) \), the product rule breaks it into \( \log_{4}x + \log_{4}z \). This method shows how powerful and efficient the property can be in simplifying seemingly complicated expressions.
Quotient Rule for Logarithms
An important rule in logarithms is the quotient rule, which deals with division. This rule states that the logarithm of a quotient is the difference between the logarithms of the numerator and the denominator. It can be written mathematically as \( \log_b(\frac{M}{N}) = \log_b M - \log_b N \). This rule helps to break down complex division operations into more manageable subtraction problems.
  • Allows for easier manipulation of dividing expressions.
  • Simplifies solving equations involving division within logs.
In practical application, as shown in the exercise with the expression \( \log_{4}(y/x) \), the quotient rule transforms it into \( \log_{4}y - \log_{4}x \). By using this property, dividing two numbers and then taking the log becomes as simple as subtracting two logarithms. It is an essential tool for efficiently handling expressions that involve division.
Power Rule for Logarithms
The power rule is a key property of logarithms that allows you to handle exponential expressions with ease. It states that the logarithm of a number raised to an exponent is the exponent multiplied by the logarithm of the base number. Mathematically, it's expressed as \( \log_b(M^k) = k \cdot \log_b M \). This rule is particularly useful when simplifying expressions where a variable is raised to a power.
  • Makes it easy to work with exponential growth problems.
  • Models real-world applications involving powers and roots effectively.
In the exercise example \( \log_{4} \sqrt[3]{z} \), we recognize \( \sqrt[3]{z} \) as \( z^{1/3} \). Applying the power rule, it simplifies to \( \frac{1}{3} \times \log_{4}z \). This demonstrates how the power rule can transform complex powers or roots into simple multiples, expediting the calculation process.

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Most popular questions from this chapter

Find an exponential function of the form \(f(x)=b a^{-x}+c\) that has the given horizontal asymptote and \(y\) -intercept and passes through point \(P .\) $$y=72 ; \quad y \text { -intercept } 425 ; \quad P(1,248.5)$$

In 1840 , Britain experienced a bovine (cattle and oxen) epidemic called epizooty. The estimated number of new cases every 28 days is listed in the table. At the time, the London Daily made a dire prediction that the number of new cases would continue to increase indefinitely. William Farr correctly predicted when the number of new cases would peak. Of the two functions $$\begin{array}{l}f(t)=653(1.028)^{t} \\\g(t)=54,700 e^{-(t-200)^{2} / 7500}\end{array}$$ and one models the newspaper's prediction and the other models Farr's prediction, where \(t\) is in days with \(t=0\) corresponding to August \(12,1840\). $$\begin{array}{|c|c|}\hline \text { Date } & \text { New cases } \\\\\hline \text { Aug. 12 } & 506 \\\\\hline \text { Sept. 9 } & 1289 \\\\\hline \text { Oct. 7 } & 3487 \\\\\hline \text { Nov. 4 } & 9597 \\\\\hline \text { Dec. 2 } & 18,817 \\\\\hline \text { Dec. 30 } & 33,835 \\\\\hline \text { Jan. 27 } & 47,191 \\\\\hline\end{array}$$ (a) Graph each function, together with the data, in the viewing rectangle \([0,400,100]\) by \([0,60,000,10,000]\) (b) Determine which function better models Farr's prediction. (c) Determine the date on which the number of new cases peaked.

Air pressure The air pressure \(p(h)\) (in \(\mathrm{Ib} / \mathrm{in}^{2}\) ) at an altitude of \(h\) feet above sea level may be approximated by the formula \(p(h)=14.7 e^{-0.0000385 h}\). At approximately what altitude \(h\) is the air pressure (a) \(10 \mathrm{lb} / \mathrm{in}^{2} ?\) (b) one-half its value at sea level?

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Exer. \(47-48\) : Sketch the graph of \(f,\) and use the change of base formula to approximate the \(y\) -intercept. $$f(x)=\log _{3}(x+5)$$

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