Chapter 4: Problem 36
Find an exponential function of the form \(f(x)=b a^{-x}+c\) that has the given horizontal asymptote and \(y\) -intercept and passes through point \(P .\) $$y=72 ; \quad y \text { -intercept } 425 ; \quad P(1,248.5)$$
Short Answer
Expert verified
The function is \( f(x) = 353 \cdot 2^{-x} + 72 \).
Step by step solution
01
Identify Known Parameters
We have the horizontal asymptote at \( y = 72 \), so \( c = 72 \). The \( y \)-intercept is \( 425 \), which means \( f(0) = 425 \). The point \( P(1, 248.5) \) is on the curve, so we have \( f(1) = 248.5 \).
02
Substitute into Function: Y-Intercept
Using the \( y \)-intercept, substitute into the function: \( 425 = b a^{-0} + 72 \). Thus, \( 425 = b + 72 \). Solving gives us \( b = 425 - 72 = 353 \).
03
Substitute into Function: Point P
Using the point \( P(1, 248.5) \), substitute into the function: \( 248.5 = 353 a^{-1} + 72 \). Simplify this to find \( a \).
04
Solve for a
Rearrange the equation \( 248.5 = \frac{353}{a} + 72 \) to find \( a \): substract 72 from both sides to get \( 176.5 = \frac{353}{a} \). Multiply through by \( a \) and divide to get \( a = \frac{353}{176.5} \). Calculate to find \( a \approx 2 \).
05
Final Exponential Function
With \( b = 353 \), \( a \approx 2 \), and \( c = 72 \), the function is \( f(x) = 353 \cdot 2^{-x} + 72 \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Horizontal Asymptote
In the world of exponential functions, the horizontal asymptote is a line that the graph approaches but never quite touches. This line represents the value that the function will get infinitely close to as the input values become very large in a positive or negative direction. For the function description given in the exercise, the horizontal asymptote was at \( y = 72 \). This helped us identify that the parameter \( c \) in the function \( f(x) = b a^{-x} + c \) equals 72.
This value essentially tells us the long-term behavior of the function. As \( x \) becomes very large, the term \( b a^{-x} \) shrinks towards zero, making the function value approach \( c \), which is 72 in this case.
Understanding horizontal asymptotes is crucial for graphing and analyzing the long-term trends of exponential functions.
This value essentially tells us the long-term behavior of the function. As \( x \) becomes very large, the term \( b a^{-x} \) shrinks towards zero, making the function value approach \( c \), which is 72 in this case.
Understanding horizontal asymptotes is crucial for graphing and analyzing the long-term trends of exponential functions.
Y-Intercept
The \( y \)-intercept of a function is the point where the graph crosses the \( y \)-axis. It is found by evaluating the function at \( x = 0 \). For the exercise, the \( y \)-intercept was given as 425, which indicates that when \( x = 0 \), \( f(x) = 425 \). This information allowed us to solve for \( b \) in the function \( f(x) = b a^{-x} + 72 \).
By setting \( x = 0 \) in the equation, we know:
By setting \( x = 0 \) in the equation, we know:
- \( 425 = b \cdot a^{0} + 72 \)
- Since \( a^{0} = 1 \), the equation simplifies to \( 425 = b + 72 \)
Exponential Equation Solving
Solving exponential equations involves finding unknown parameters that define the behavior of the function. In the given exercise, we knew the horizontal asymptote \( c \), the \( y \)-intercept which gave us \( b \), and had the point \( P(1, 248.5) \) which allowed us to solve for \( a \).
The pivotal step involved substituting point \( P \) into the equation:
\[ 248.5 = 353 \cdot 2^{-1} + 72 \]
This equation rearranges and solves for \( a \), verifying it through:
The pivotal step involved substituting point \( P \) into the equation:
\[ 248.5 = 353 \cdot 2^{-1} + 72 \]
This equation rearranges and solves for \( a \), verifying it through:
- Subtract 72 from 248.5 to isolate terms involving \( a \)
- Multiply both sides by \( a \) to remove the denominator
- Finally, result in \( a \approx 2 \)
Function Parameters
Parameters in an exponential function define its shape and behavior. In our case, these parameters were \( b \), \( a \), and \( c \). Each one plays a unique role in constructing the specific function.
Let's quickly review them:
Let's quickly review them:
- \( b \): This represents the "amplitude" factor, shifting the function vertically and affecting how "steep" the function starts. We found \( b = 353 \) using the given \( y \)-intercept.
- \( a \): Known as the base of the exponent, \( a \) dictates the rate of exponential growth or decay. In this exercise, we calculated \( a \approx 2 \), implying it determines how fast the function values decrease as \( x \) increases.
- \( c \): The parameter \( c \) denotes the horizontal asymptote's value, dictating the level to which the graph eventually settles, which is 72 for this problem.