Chapter 2: Problem 15
(a) Use the quadratic formula to find the zeros of \(f .\) (b) Find the maximum or minimum value of \(f(x)\) (c) Sketch the graph of \(f\) $$f(x)=-12 x^{2}+11 x+15$$
Short Answer
Expert verified
The zeros are \( x = -\frac{3}{4} \) and \( x = \frac{5}{3} \), the maximum value is approximately \( 8.52 \), and the graph is a downward-opening parabola.
Step by step solution
01
Identify the coefficients
The quadratic function is given by \( f(x) = -12x^2 + 11x + 15 \). Identify the coefficients: \( a = -12 \), \( b = 11 \), and \( c = 15 \).
02
Apply the quadratic formula
The quadratic formula is \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \). Substitute the coefficients: \( x = \frac{-11 \pm \sqrt{11^2 - 4(-12)(15)}}{2(-12)} \).
03
Calculate the discriminant
Calculate \( b^2 - 4ac \) to find the discriminant. \( 11^2 - 4(-12)(15) = 121 + 720 = 841 \).
04
Solve for the roots
Since the discriminant is a perfect square, find the exact roots: \( x = \frac{-11 \pm \sqrt{841}}{-24} \). Simplify to \( x = \frac{-11 \pm 29}{-24} \). Thus, \( x_1 = \frac{-11 + 29}{-24} = \frac{18}{-24} = -\frac{3}{4} \) and \( x_2 = \frac{-11 - 29}{-24} = \frac{-40}{-24} = \frac{5}{3} \).
05
Determine the vertex
The vertex form of a parabola is \( x = -\frac{b}{2a} \). Substitute the values: \( x = -\frac{11}{2(-12)} = \frac{11}{24} \).
06
Find the maximum or minimum value
To find \( f(\frac{11}{24}) \), substitute back into the equation: \( f(\frac{11}{24}) = -12(\frac{11}{24})^2 + 11(\frac{11}{24}) + 15 \). Calculate \( f(\frac{11}{24}) = -\frac{121}{48} + \frac{121}{24} + 15 \). Simplify to find \( f(\frac{11}{24}) = \frac{409}{48} \), which is approximately \( 8.52 \). This is a maximum since \( a = -12 \) is negative.
07
Sketch the graph of the function
Sketch a parabola opening downwards with vertex at \( \left(\frac{11}{24}, \frac{409}{48}\right) \), and x-intercepts at \( x = -\frac{3}{4} \) and \( x = \frac{5}{3} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
To solve a quadratic equation like \( f(x) = -12x^2 + 11x + 15 \), we can use the quadratic formula. This method helps find the 'zeros' or 'roots' of the quadratic function, which are the values of \( x \) where \( f(x) = 0 \).
The quadratic formula is represented as:
Using this method, it's crucial to calculate the discriminant first, \( b^2 - 4ac \), which will determine the nature of the roots. Positive discriminants indicate two distinct real roots, negative ones imply complex roots, and a zero discriminant reveals a repeated real root. Now, substitute these values and solve the equation to find your answers.
The quadratic formula is represented as:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
Using this method, it's crucial to calculate the discriminant first, \( b^2 - 4ac \), which will determine the nature of the roots. Positive discriminants indicate two distinct real roots, negative ones imply complex roots, and a zero discriminant reveals a repeated real root. Now, substitute these values and solve the equation to find your answers.
Vertex Form
The vertex of a parabola is a key feature, as it represents the highest or lowest point on the graph, depending on the orientation. While our original quadratic is in the standard form, \( ax^2 + bx + c \), the vertex form is expressed as:
To find the vertex using the standard form, we can calculate \( h \) using \(-\frac{b}{2a}\). For \( f(x) = -12x^2 + 11x + 15 \), we found \( h = \frac{11}{24} \). The next step is to find \( k \), the maximum or minimum value of the function when \( x = h \), by substituting back into the equation to get \( f(h) \).
In this specific case, the function reaches a maximum value since the parabola opens downwards (due to \( a = -12 \) being negative). The vertex for this function is approximately \( \left(\frac{11}{24}, 8.52\right) \). Understanding the vertex form is essential, especially for graphing and analyzing the properties of the parabola.
- \( y = a(x-h)^2 + k \)
To find the vertex using the standard form, we can calculate \( h \) using \(-\frac{b}{2a}\). For \( f(x) = -12x^2 + 11x + 15 \), we found \( h = \frac{11}{24} \). The next step is to find \( k \), the maximum or minimum value of the function when \( x = h \), by substituting back into the equation to get \( f(h) \).
In this specific case, the function reaches a maximum value since the parabola opens downwards (due to \( a = -12 \) being negative). The vertex for this function is approximately \( \left(\frac{11}{24}, 8.52\right) \). Understanding the vertex form is essential, especially for graphing and analyzing the properties of the parabola.
Discriminant
The discriminant in a quadratic equation is derived from the expression under the square root in the quadratic formula, \( \sqrt{b^2 - 4ac} \). This value, \( b^2 - 4ac \), helps determine the nature of the roots of the quadratic equation. A detailed examination of the discriminant can reveal the following:
- If the discriminant is positive, the quadratic equation has two distinct real roots.
- If it is zero, there is exactly one real root (a repeated root).
- If it is negative, the roots are complex or imaginary numbers.
Parabola
A parabola is the graph that represents a quadratic function like \( f(x) = ax^2 + bx + c \). The shape of a parabola is crucial as it tells us important aspects of the quadratic equation's behavior.
Here are some key characteristics of a parabola:
Here are some key characteristics of a parabola:
- If \( a \) is positive, the parabola opens upwards, indicating a minimum vertex.
- If \( a \) is negative, the parabola opens downwards, indicating a maximum vertex.
- The vertex is the turning point of the parabola.
- The axis of symmetry passes through the vertex, dividing the parabola into two mirror-image halves.