Chapter 2: Problem 16
(a) Use the quadratic formula to find the zeros of \(f .\) (b) Find the maximum or minimum value of \(f(x)\) (c) Sketch the graph of \(f\) $$f(x)=6 x^{2}+7 x-24$$
Short Answer
Expert verified
The zeros are \( x = \frac{3}{2} \) and \( x = -\frac{8}{3} \), with a minimum value \(-\frac{625}{24}\) at \( x = -\frac{7}{12} \).
Step by step solution
01
Identify the quadratic equation
We begin by identifying the quadratic equation given: \[ f(x) = 6x^2 + 7x - 24 \] This is in standard form, where \( a = 6 \), \( b = 7 \), and \( c = -24 \).
02
Apply the quadratic formula
The quadratic formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Substitute the values of \( a \), \( b \), and \( c \):\[ x = \frac{-7 \pm \sqrt{7^2 - 4 \cdot 6 \cdot (-24)}}{2 \cdot 6} \] Continue simplifying.
03
Calculate the discriminant
Calculate the discriminant \( \Delta = b^2 - 4ac \):\[ \Delta = 7^2 - 4 \cdot 6 \cdot (-24) = 49 + 576 = 625 \]
04
Find the square root of the discriminant
Since \( \Delta = 625 \), and the square root is:\[ \sqrt{625} = 25 \]
05
Solve for zeros
Substitute \( \sqrt{625} \) back into the quadratic formula:\[ x = \frac{-7 \pm 25}{12} \] Calculate the solutions: \[ x_1 = \frac{-7 + 25}{12} = \frac{18}{12} = \frac{3}{2} \]\[ x_2 = \frac{-7 - 25}{12} = \frac{-32}{12} = -\frac{8}{3} \] Thus, the roots (zeros) are \( x = \frac{3}{2} \) and \( x = -\frac{8}{3} \).
06
Determine the vertex using vertex form
The vertex form for a quadratic function is \( x = -\frac{b}{2a} \), which will give us the x-coordinate of the vertex:\[ x = -\frac{7}{2 \cdot 6} = -\frac{7}{12} \]
07
Calculate the minimum or maximum value
Substitute \( x = -\frac{7}{12} \) back into the function to find the corresponding y-coordinate:\[ f\left(-\frac{7}{12}\right) = 6 \left(-\frac{7}{12}\right)^2 + 7 \left(-\frac{7}{12}\right) - 24 \]First, calculate each term and then add them together:\[ 6 \left(\frac{49}{144}\right) = \frac{49}{24} \]\[ 7 \left(-\frac{7}{12}\right) = -\frac{49}{12} \]Final value:\[ = \frac{49}{24} - \frac{98}{24} - \frac{576}{24} = \frac{-625}{24} \]Thus, \( f(x) \) has a minimum value of \( -\frac{625}{24} \) at \( x = -\frac{7}{12} \).
08
Sketch the graph
Using the information obtained:- Vertex: \((-\frac{7}{12}, -\frac{625}{24})\)- Zeros: \( x = \frac{3}{2}, x = -\frac{8}{3} \)The graph is a parabola opening upwards due to the positive coefficient of \( x^2 \). Draw the two solutions on the x-axis and mark the vertex below the x-axis.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a vital tool for solving quadratic equations. These equations take the form:\[ ax^2 + bx + c = 0 \]where \(a\), \(b\), and \(c\) are constants, and \(a eq 0\). The quadratic formula allows you to find the roots (or zeros) of the equation, and it is given by:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Using this formula, you can ensure that you account for complex and real solutions. The part under the square root, \(b^2 - 4ac\), is called the discriminant. Solving quadratic equations using this formula is efficient and clear, especially because it provides a systematic way to arrive at the solutions without needing to factor the quadratic expression manually.
Discriminant
In the context of quadratic equations, the discriminant plays a crucial role in determining the nature of the roots. It is the expression found under the square root in the quadratic formula: \(b^2 - 4ac\). This value can tell us a lot about the equation:
- If the discriminant \(\Delta > 0\), the quadratic equation has two distinct real roots.
- If \(\Delta = 0\), there is exactly one real root, which means the graph touches the x-axis at a single point.
- If \(\Delta < 0\), the equation has no real roots, and instead, there are two complex conjugate roots.
Vertex of a Quadratic Function
The vertex of a quadratic function is an essential feature of its graph, as it represents the point where the function changes direction. For the standard form \(ax^2 + bx + c\) of a quadratic equation, the x-coordinate of the vertex is given by:\[ x = -\frac{b}{2a} \]This formula gives a quick way to find where the vertex lies on the x-axis. Once the x-value is determined, substitute it back into the quadratic function to find the corresponding y-coordinate. This point \((x, y)\) is the vertex.
- If the parabola opens upwards (\(a > 0\)), the vertex is the minimum point.
- If the parabola opens downwards (\(a < 0\)), the vertex is the maximum point.
Graphing Parabolas
Graphing parabolas involves understanding the shape and key points of the quadratic function's graph. The fundamental characteristics of a parabola include its vertex, direction of opening, and roots or zeros:
- Vertex: The turning point of the parabola, which we calculated as \((-\frac{7}{12}, -\frac{625}{24})\) in our example.
- Zeros (Roots): The x-values where the parabola intersects the x-axis, calculated using the quadratic formula.
- Opening Direction: Determined by the sign of \(a\); if positive, the parabola opens upwards, as seen here with \(a = 6\).