/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 Use the binomial theorem to expa... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the binomial theorem to expand and simplify. $$\left(x^{2}+2 y\right)^{3}$$

Short Answer

Expert verified
The expanded form is \(x^6 + 6x^4y + 12x^2y^2 + 8y^3\).

Step by step solution

01

Identifying the Binomial Theorem

The binomial theorem states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^{k}\). Here, \(a = x^2\), \(b = 2y\), and \(n = 3\). We will use this formula to expand the expression.
02

Calculation of Coefficients

We calculate the binomial coefficients \(\binom{3}{k}\) for \(k = 0, 1, 2, 3\). - \(\binom{3}{0} = 1\) - \(\binom{3}{1} = 3\) - \(\binom{3}{2} = 3\) - \(\binom{3}{3} = 1\) These coefficients will be used in the expansion.
03

Expanding Using the Binomial Formula

Substitute the values into the binomial formula:\[ (x^2 + 2y)^3 = \binom{3}{0} (x^2)^{3-0} (2y)^{0} + \binom{3}{1} (x^2)^{3-1} (2y)^{1} + \binom{3}{2} (x^2)^{3-2} (2y)^{2} + \binom{3}{3} (x^2)^{3-3} (2y)^{3} \]
04

Simplifying Each Term

Now, simplify each term of the expansion:- \( \binom{3}{0} (x^2)^3 (2y)^0 = 1 \cdot x^6 \cdot 1 = x^6 \)- \( \binom{3}{1} (x^2)^2 (2y)^1 = 3 \cdot x^4 \cdot 2y = 6x^4y \)- \( \binom{3}{2} (x^2)^1 (2y)^2 = 3 \cdot x^2 \cdot 4y^2 = 12x^2y^2 \)- \( \binom{3}{3} (x^2)^0 (2y)^3 = 1 \cdot 1 \cdot 8y^3 = 8y^3 \)
05

Combining Simplified Terms

Combine all the terms from the expansion to form the final expression: \[ x^6 + 6x^4y + 12x^2y^2 + 8y^3 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficients
In algebra, binomial coefficients are a key component in the binomial theorem, which is used for expanding expressions that involve powers of binomials. Binomial coefficients refer to the numbers in front of each term in binomial expansions and are commonly represented as \( \binom{n}{k} \). These coefficients can be found in Pascal's Triangle, where each number is the sum of the two directly above it. For example, in the expression given by \( (a + b)^3 \), the coefficients are \( \binom{3}{0}, \binom{3}{1}, \binom{3}{2}, \binom{3}{3} \), which equal 1, 3, 3, and 1, respectively.
  • Each coefficient \( \binom{n}{k} \) denotes the number of ways to choose \( k \) elements from \( n \), emphasizing its combinatorial nature.
  • These coefficients multiply the successive combinations of powers of \( a \) and \( b \) in the expansion.
  • To calculate them directly, you can use the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \).
Understanding binomial coefficients is essential as they dictate the contribution of each term in a binomial expansion, providing structure to the polynomial.
Binomial Expansion
Binomial expansion is a method in algebra used to express the power of a binomial as a polynomial. It leverages the binomial theorem which states that \( (a + b)^n \) can be expanded into sum of terms involving binomial coefficients. Each term in the expansion can be represented in the form \( \binom{n}{k} a^{n-k} b^{k} \).
  • The expansion is a sum of terms of increasing powers of \( b \), starting from 0 up to \( n \), while the power of \( a \) correspondingly decreases from \( n \) to 0.
  • This approach is extremely useful when manually expanding expressions like \( (x^2 + 2y)^3 \), as it simplifies the process.
For instance, in the example \( (x^2 + 2y)^3 \), binomial expansion gives \[ x^6 + 6x^4y + 12x^2y^2 + 8y^3 \], representing a systematic way of expanding, critical for solving polynomial algebraic expressions.
Algebraic Expressions
Algebraic expressions are combinations of numbers, variables, and operations that together represent a mathematical concept. They form the core of algebraic problem solving. In dealing with problems like expanding \( (x^2 + 2y)^3 \), understanding and manipulating these expressions through operations like binomial expansion facilitates solving complex algebra problems.
  • Algebraic expressions often involve powers, products, and sums, which require careful handling to maintain equality.
  • In binomial expansions, recognizing that expressions like \( x^2 \) and \( 2y \) are treated as single algebraic terms is crucial.
Mastering the skill of manipulating algebraic expressions is key, as it helps in simplifying complex problems and forming the foundation for higher-level mathematics. By understanding how to interpret and expand expressions, one can solve a wide range of mathematical challenges.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The outcomes \(1,2, \ldots, 6\) of an experiment and their probabilities are listed in the table. $$\begin{array}{l|cccccc}\\\\\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Probability } & 0.25 & 0.10 & 0.15 & 0.20 & 0.25 & 0.05 \\\\\hline\end{array}$$.For the Indicated events, find (a) \(P\left(E_{2}\right),\) (b) \(P\left(E_{1} \cap E_{2}\right)\) (c) \(P\left(E_{1} \cup E_{2}\right),\) and \((d) P\left(E_{2} \cup E_{3}^{\prime}\right)\). $$E_{1}=\\{1,2,3,6\\} ; \quad E_{2}=\\{3,4\\} ; \quad E_{3}=\\{4,5,6\\}$$

Exer. \(67-70\) : For the given \(n\) th term \(a_{n}=f(n)\) of a sequence, use the graph of \(y=f(x)\) on the interval \([1,100]\) to verify that as \(n\) increases without bound, \(a_{n}\) approaches some real number \(c\) $$a_{n}=\left(\frac{1}{n}\right)^{1 / n}$$

Bode's requence Bode's sequence, defined by $$ a_{1}=0.4, \quad a_{k}=0.1\left(3 \cdot 2^{k-2}+4\right) \quad \text { for } \quad k \geq 2 $$ can be used to approximate distances of planets from the sun. These distances are measured in astronomical units, with \(1 \mathrm{AU}=93,000,000 \mathrm{mi}\). For example, the third term corresponds to Earth and the fifth term to the minor planet Ceres. Approximate the first five terms of the sequence.

Exer. \(61-62:\) Some calculators use an algorithm similar to the following to approximate \(\sqrt{N}\) for a positive real number \(N:\) Let \(x_{1}=N / 2\) and find successive approximations \(x_{2}, x_{3}, \ldots\) by using $$ x_{2}=\frac{1}{2}\left(x_{1}+\frac{N}{x_{1}}\right), \quad x_{3}=\frac{1}{2}\left(x_{2}+\frac{N}{x_{2}}\right), \quad \dots $$ until the desired accuracy is obtained. Use this method to approximate the radical to six-decimal-place accuracy. $$\sqrt{5}$$

That girl-boy births are equally probable, find the probability that a family with five children has (a) all boys (b) at least one girl

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.