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Use the binomial theorem to expand and simplify. $$(4 x-y)^{3}$$

Short Answer

Expert verified
\(64x^3 - 48x^2y + 12xy^2 - y^3\)

Step by step solution

01

Understand the Binomial Theorem

The binomial theorem provides a way to expand expressions of the form \((a + b)^n\). It states that \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k}a^{n-k}b^k\). Here, \(\binom{n}{k}\) is a binomial coefficient.
02

Identify the Components

In our expression \((4x - y)^3\), we can identify \(a = 4x\), \(b = -y\), and \(n = 3\). We will substitute these into the binomial theorem formula.
03

Apply the Binomial Theorem

Using the binomial theorem, we expand \((4x - y)^3\) as:\[(4x - y)^3 = \sum_{k=0}^{3} \binom{3}{k} (4x)^{3-k} (-y)^k\]
04

Calculate Each Term

Calculate each term in the expansion:- For \(k = 0\): \(\binom{3}{0}(4x)^3(-y)^0 = 1 \, \times \, 64x^3 \, \times \, 1 = 64x^3\)- For \(k = 1\): \(\binom{3}{1}(4x)^2(-y)^1 = 3 \, \times \, 16x^2 \, \times \, (-y) = -48x^2y\)- For \(k = 2\): \(\binom{3}{2}(4x)^1(-y)^2 = 3 \, \times \, 4x \, \times \, y^2 = 12xy^2\)- For \(k = 3\): \(\binom{3}{3}(4x)^0(-y)^3 = 1 \, \times \, 1 \, \times \, -y^3 = -y^3\)
05

Combine the Terms

Combine all the calculated terms: \(64x^3 - 48x^2y + 12xy^2 - y^3\). This is the expanded and simplified form of the original expression.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient is a fundamental component of the binomial theorem, represented by \( \binom{n}{k} \). It determines the number of ways to choose \( k \) elements from a set of \( n \) elements, and is crucial when expanding polynomials using the binomial theorem.

Mathematically, the binomial coefficient is expressed as:
  • \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)
where \( n! \) (n factorial) is the product of all positive integers up to \( n \).

In a polynomial expansion such as \((4x-y)^3\), each term in the expansion is paired with a specific binomial coefficient.
For example, when \( k = 0 \) the binomial coefficient is \( \binom{3}{0} = 1 \), while for \( k = 1 \) it is \( \binom{3}{1} = 3 \).

The coefficients help dictate the weight of each corresponding term in the expanded polynomial, allowing accurate calculations.
Polynomial Expansion
Polynomial expansion using the binomial theorem allows expressions like \((a+b)^n\) to be expanded into a sum of terms involving powers of \(a\) and \(b\).

Each term in the expansion consists of:
  • A binomial coefficient \( \binom{n}{k} \)
  • The expression \( a^{n-k} \)
  • The expression \( b^k \)
For the given problem \((4x-y)^3\), the expansion process involves identifying components \(a = 4x\), \(b = -y\), and \(n = 3\), then using them within the binomial formula:
  • The first term is \( \binom{3}{0}(4x)^{3}( -y)^{0} = 64x^3 \)
  • The second term is \( \binom{3}{1}(4x)^{2}( -y)^{1} = -48x^2y \)
  • The third term is \( \binom{3}{2}(4x)^{1}( -y)^{2} = 12xy^2 \)
  • The fourth term is \( \binom{3}{3}(4x)^{0}( -y)^{3} = -y^3 \)
By calculating each of these terms separately, you can then add them to achieve the expanded expression \(64x^3 - 48x^2y + 12xy^2 - y^3\), providing insight into the structure of the polynomial.
Mathematics Problem Solving
Solving math problems involves a clear and methodical approach to ensure understanding and accuracy. In the context of the binomial theorem, problem-solving begins with understanding the expression you're working with and the method you need to apply.

First, recognize the form of the problem, such as \((a + b)^n\), and correctly identify \(a\), \(b\), and \(n\).

Next, apply the appropriate theorem or method—in this case, the binomial theorem—to expand the expression.

Then, compute each term, utilizing tools like the binomial coefficient to help determine the contribution of different terms in the polynomial.

Finally, sum the calculated terms to form the expanded and simplified polynomial, checking for accuracy throughout each step.

This structured approach helps break down complex problems into manageable steps, promoting better understanding and a successful solution.

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Most popular questions from this chapter

The equation \(\frac{1}{3} \sqrt[3]{x}-x+2=0\) has a root near \(2 .\) To approximate this root, rewrite the equation as \(x=\frac{1}{3} \sqrt[3]{x}+2\) Let \(x_{1}=2\) and find successive approximations \(x_{2}, x_{3}, \ldots\) by using the formulas $$ x_{2}=\frac{1}{3} \sqrt[3]{x_{1}}+2, \quad x_{3}=\frac{1}{3} \sqrt[3]{x_{2}}+2, \quad \ldots $$ until four-decimal-place accuracy is obtained.

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