/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Simplify. $$\left(\frac{1}{3} ... [FREE SOLUTION] | 91Ó°ÊÓ

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Simplify. $$\left(\frac{1}{3} x^{4} y^{-3}\right)^{-2}$$

Short Answer

Expert verified
The simplified expression is \( \frac{9y^6}{x^8} \).

Step by step solution

01

Apply the Power of a Power Rule

The expression is \(\left( \frac{1}{3} x^{4} y^{-3} \right)^{-2}\). According to the power of a power rule, \( (a^m)^n = a^{m \cdot n} \). Apply this rule to each component inside the parentheses: \( (\frac{1}{3})^{-2} \), \( (x^4)^{-2} \), and \( (y^{-3})^{-2} \).
02

Simplify the Coefficient

For the coefficient, \( (\frac{1}{3})^{-2} \) is equivalent to \( (3^1)^{2} \). Therefore, \( (\frac{1}{3})^{-2} = 3^2 = 9 \).
03

Simplify the Variable with Positive Exponent

For \( x^{4} \): \( (x^4)^{-2} = x^{4 \cdot (-2)} = x^{-8} \).
04

Simplify the Variable with Negative Exponent

For \( y^{-3} \): \( (y^{-3})^{-2} = y^{-3 \cdot (-2)} = y^6 \). Applying the power of a power rule, multiplying two negatives makes the second power positive.
05

Combine the Simplified Expressions

Combine all the simplified parts: \( 9 \cdot x^{-8} \cdot y^6 \).
06

Rewrite with Positive Exponents

To express the term with a positive exponent, recall that \( a^{-m} = \frac{1}{a^m} \). Thus, \( x^{-8} = \frac{1}{x^8} \). The expression becomes \( \frac{9y^6}{x^8} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power of a Power Rule
The **Power of a Power Rule** is a fundamental aspect of exponentiation that simplifies expressions when an exponent is raised to another exponent. This rule states that if you have a power inside the parentheses and raise it to another power, you multiply the exponents together. Consider the mathematical expression such as \( (a^m)^n = a^{m \cdot n} \).
For instance, in the given exercise where you have \( (x^4)^{-2} \), you apply the power of a power rule by multiplying 4 and -2 to transform it into \( x^{-8} \). Similarly, with \( (y^{-3})^{-2} \), applying the rule turns it into \( y^{6} \) since the product of two negatives yields a positive, making the exponent positive.
Using this rule simplifies the calculation process considerably and is an essential technique in algebra for handling complex exponentiation expressions.
Negative Exponents
**Negative Exponents** can seem tricky at first, but they simply tell you that a number is being divided rather than multiplied. A negative exponent corresponds to the reciprocal of the base raised to the positive of that exponent. In general, \( a^{-m} = \frac{1}{a^m} \).
In the context of the exercise \((x^4)^{-2}\), the outcome is \(x^{-8}\), which further simplifies to \(\frac{1}{x^8}\), reflecting the reciprocal action implied by the negative exponent.
Similarly, when simplifying \( (y^{-3})^{-2}\), the double negative from the exponent multiplication changes it to a positive exponent, resulting in \(y^6\). Understanding negative exponents is key to simplifying expressions and rearranging them to clear, user-friendly forms.
Simplifying Expressions
**Simplifying Expressions** involves reducing them to their most basic form without changing their value, which is crucial for clearer communication in mathematics. After using exponent rules, like the power of a power and dealing with negative exponents, the next step is to combine and reduce terms.
In this exercise, after applying the power of a power rule and rewriting negative exponents, you arrive at \( 9 \cdot x^{-8} \cdot y^6 \). To further simplify, you convert \( x^{-8} \) to its reciprocal form \( \frac{1}{x^8} \), thus obtaining the simplified final expression: \( \frac{9y^6}{x^8} \).
The simplification process makes mathematical expressions easier to handle and interpret, which is especially helpful when dealing with large and complex equations.

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Most popular questions from this chapter

Archeologists can determine the height of a human without having a complete skeleton. If an archeologist finds only a humerus, then the height of the individual can be determined by using a simple linear relationship. (The humerus is the bone between the shoulder and the elbow.) For a female, if \(x\) is the length of the humerus (in centimeters), then her height \(h\) (in centimeters) can be determined using the formula \(h=65+3.14 x .\) For a male, \(h=73.6+3.0 x\) should be used. (a) A female skeleton having a 30 -centimeter humerus is found. Find the woman's height at death. (b) A person's height will typically decrease by 0.06 centimeter each year after age \(30 .\) A complete male skeleton is found. The humerus is 34 centimeters, and the man's height was 174 centimeters. Determine his approximate age at death.

Simplify the expression, and rationalize the denominator when appropriate. $$\sqrt[4]{\left(3 x^{5} y^{-2}\right)^{4}}$$

Rewrite the expression using rational exponents. $$\sqrt{a+\sqrt{b}}$$

A city government has approved the construction of an \(\$ 800\) million sports arena. Up to 5480 million will be raised by selling bonds that pay simple interest at a rate of \(6 \%\) annually. The remaining amount (up to \(\$ 640\) million) will be obtained by borrowing money from an insurance company at a simple interest rate of \(5 \% .\) Determine whether the arena can be financed so that the annual interest is \(\$ 42\) million.

Simplify the expression, and rationalize the denominator when appropriate. $$\sqrt[5]{-64}$$

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