/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Factor the polynomial. $$64 x^... [FREE SOLUTION] | 91Ó°ÊÓ

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Factor the polynomial. $$64 x^{3}+27$$

Short Answer

Expert verified
The factored form is \((4x + 3)(16x^2 - 12x + 9)\).

Step by step solution

01

Recognize the form of the polynomial

The polynomial given is \(64x^3 + 27\). Recognize this as a sum of cubes, which generally takes the form \(a^3 + b^3\). In this case, we have \(a = (4x)\) and \(b = 3\), since \((4x)^3 = 64x^3\) and \(3^3 = 27\).
02

Apply the sum of cubes formula

The formula for factoring a sum of cubes is \((a^3 + b^3) = (a + b)(a^2 - ab + b^2)\). Using the values \(a = 4x\) and \(b = 3\), substitute into the formula.
03

Calculate each part of the formula

Start by finding \(a + b = 4x + 3\). Next, calculate \(a^2 = (4x)^2 = 16x^2\). Then, find \(ab = (4x)(3) = 12x\), and \(b^2 = 3^2 = 9\).
04

Plug values into the formula

Substitute the values back into the formula: \[(4x + 3)(16x^2 - 12x + 9)\].
05

Verify the factors

Expand the factored form to ensure it results in the original cubic polynomial:First, expand \( (4x + 3) \times (16x^2 - 12x + 9) \) to confirm it equals \(64x^3 + 27\). This confirms successful factoring.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Sum of Cubes
Sum of cubes is a special type of polynomial expression. It follows the form \(a^3 + b^3\). This indicates that each term is a perfect cube. In the expression \(64x^3 + 27\), you have one term, \(64x^3\), which is \((4x)^3\) and another, \(27\), which is equal to \(3^3\).
The sum of cubes has a standardized method for factoring. This involves the formula:
  • \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\)
By utilizing this formula, you can break down the cubic expression into a product of a linear binomial and a quadratic trinomial. This method simplifies complex algebraic expressions and makes them easier to solve or integrate into more advanced mathematical processes. For many students, understanding and applying this formula is a breakthrough moment in mastering polynomial expressions.
Breaking Down Algebraic Expressions
Algebraic expressions come in different forms, ranging from simple terms like \(x\) or \(y\), to more complex forms such as \(a^3 + b^3\). Understanding how to manipulate these expressions is key in algebra.
The first step is identifying the different elements within an expression:
  • Coefficients (e.g., 64 in \(64x^3\), representing the number multiplied by the variable)
  • Variables (e.g., \(x\) in \(64x^3\))
  • Exponents (e.g., 3 as in \(x^3\), indicating how many times the variable is multiplied by itself)
Recognizing these components helps in transforming expressions by applying mathematical operations, such as factoring. Operations such as factoring sum of cubes can reduce complex expressions into simpler forms for easier handling.
When broken down, algebraic expressions don't appear so intimidating, and their structure can reveal the best ways to manipulate or simplify them.
Basics of Polynomial Factorization
Polynomial factorization is a method used for expressing a polynomial as a product of its factors. This is essential for solving polynomial equations, simplifying expressions, or finding roots.
When dealing with polynomials, such as the sum of cubes \(64x^3 + 27\), factorization is achieved by using formulas designed for specific forms. For the sum of cubes, the formula \(a^3 + b^3 = (a + b)(a^2 - ab + b^2)\) becomes useful.
  • The first step is identifying terms: \(a = 4x\) and \(b = 3\).
  • Next, substitute into the formula to identify factors: \((4x + 3)(16x^2 - 12x + 9)\).
After factorization, verification can be performed by expanding the factors. This ensures you've correctly transformed the polynomial into its factorized form. Successfully factoring polynomials can aid in solving equations or understanding deeper algebraic concepts, making it a valuable skill for students.

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