/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Begin by graphing \(f(x)=2^{x}\)... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Begin by graphing \(f(x)=2^{x}\). Then use transformations of this graph to graph the given function. Be sure to graph and give equations of the asymptotes. Use the graphs to determine each function's domain and range. If applicable, use a graphing utility to confirm your hand-drawn graphs. $$g(x)=-2^{x}$$

Short Answer

Expert verified
The graphs of \(f(x) = 2^x\) and \(g(x) = -2^x\) are reflections of each other across the x-axis. Both have a horizontal asymptote at y = 0, but no vertical asymptotes. Their domains are all real numbers. The range of \(f(x) = 2^x\) is (0, +∞), while the range of \(g(x) = -2^x\) is (-∞, 0). These conclusions are confirmed by graphing the functions with a graphing utility.

Step by step solution

01

Graphing the original function

Start by graphing \(f(x) = 2^x\). This is a basic exponential function, which starts from the point (0,1), rises quickly to the right, and very slowly descends to zero as x approaches negative infinity. The graph never touches the x-axis, making it the horizontal asymptote.
02

Transforming the function

Now graph the function \(g(x) = -2^x\). This is a reflection of \(f(x)\) in the x-axis, because the negative sign flips the function upside down. Now it descends rapidly to the left and slowly approaches zero as x goes to positive infinity. The x-axis is still the horizontal asymptote, but now the graph is below the x-axis.
03

Determine the Asymptotes

The equation of the horizontal asymptote for both \(f(x) = 2^x\) and \(g(x) = -2^x\) is y = 0, which is the x-axis. These functions do not have vertical asymptotes.
04

Determine the Domain and Range

For any exponential function, the domain is all real numbers. However, the range differs depending if the function is positive or negative. For \(f(x) = 2^x\), the range is (0, +∞) because the function is positive and it never touches the x-axis. For \(g(x) = -2^x\), the range is (-∞, 0) because the function is negative and the graph exists below the x-axis.
05

Confirm with a Graphing Utility

Finally, verify these graphs using a graphing utility. Plotting both will show that they are reflections of each other across the x-axis, confirming the hand-drawn graphs.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Transformation of Graphs
The process of transforming graphs involves taking a known graph and applying certain changes to produce a new graph. When we transform an exponential function, like the basic function of \( f(x) = 2^x \), distinct transforms such as shifting, scaling, and reflecting can be applied.

For example, the exercise presents the transformation of \( f(x) = 2^x \) into \( g(x) = -2^x \). This is a reflection about the x-axis. When reflecting a graph across an axis, each point \( (x, y) \) of the original graph is mapped to \( (x, -y) \) for a reflection across the x-axis, which creates a mirror image of the graph on the opposite side of the axis. It's important to note the behavior of the graph before and after transformation. The original function \( f(x) = 2^x \) rises quickly as x increases, whereas the transformed function \( g(x) = -2^x \) falls rapidly as x decreases, showcasing the impact of this specific transformation.
Exponential Function Domain and Range
When discussing exponential functions, understanding the domain and range is crucial. The domain of a function refers to all possible input values, while the range refers to all possible output values.

In the realm of exponential functions like \( f(x) = 2^x \), the domain is all real numbers. This is because we can raise 2 to any power, whether it's positive, negative, or zero. Meanwhile, the range is more restrictive due to the nature of exponential growth or decay. For the positive exponential function \( f(x) = 2^x \), it grows without bound as x increases, but always remains above the x-axis. Therefore, its range is \( (0, +\infty) \).

Conversely, for \( g(x) = -2^x \), the graph is flipped below the x-axis due to the negative sign. Here, the outputs are restricted to negative values, giving us a range of \( (-\infty, 0) \). This mirrors the output behavior of the original function but on the negative side of the y-axis. It is essential for students to analyze the graph to correctly interpret and identify the domain and range of these functions.
Horizontal Asymptotes
Understanding horizontal asymptotes is essential when graphing exponential functions. A horizontal asymptote is a horizontal line that a graph approaches as x goes towards infinity or negative infinity. It represents a value the function will get closer and closer to, but never actually reach.

In the case of both \( f(x) = 2^x \) and \( g(x) = -2^x \), the horizontal asymptote is the line \( y = 0 \), which is also the x-axis. Regardless of whether x is positive or negative infinity, the value of \( 2^x \) for \( f(x) \) will never become zero, just infinitely close to it. Likewise, for \( g(x) \), the magnitude of the outputs can become very small, but it will never cross the x-axis.

This concept is often where students need clarification, but a good way to visualize it is to think of the horizontal asymptote as the 'untouchable line' for the graph. It dictates the direction that the graph takes as the independent variable becomes very large or very small. Recognizing horizontal asymptotes helps in understanding the end behavior of functions and is a valuable part of analyzing graphs comprehensively.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Without using a calculator, find the exact value of $$ \frac{\log _{3} 81-\log _{\pi} 1}{\log _{2 \sqrt{2}} 8-\log 0.001} $$

From 1970 through \(2010 .\) The data are shown again in the table. Use all five data points to solve Exercises \(70-74\). $$\begin{array}{cc}\hline \begin{array}{c}x, \text { Number of Years } \\\\\text { after } 1969 \end{array} & \begin{array}{c}y, \text { U.S. Population } \\\\\text { (millions) }\end{array} \\ \hline 1(1970) & 203.3 \\\11(1980) & 226.5 \\\21(1990) & 248.7 \\\31(2000) & 281.4 \\\41(2010) & 308.7 \end{array}$$ Use your graphing utility's power regression option to obtain a model of the form \(y=a x^{b}\) that fits the data. How well does the correlation coefficient, \(r,\) indicate that the model fits the data?

The formula \(S=C(1+r)^{t}\) models inflation, where \(C=\) the value today, \(r=\)the annual inflation rate, and \(S=\)the inflated value t years from now. Use this formula to solve. Round answers to the nearest dollar. A decimal approximation for \(\pi\) is \(3.141593 .\) Use a calculator to find \(2^{3}, 2^{3.1}, 2^{3.14}, 2^{3.141}, 2^{3.1415}, 2^{3.14159},\) and \(2^{3.141593} .\) Now find \(2^{\pi}\). What do you observe?

Exercises \(153-155\) will help you prepare for the material covered in the next section. U.S. soldiers fight Russian troops who have invaded New York City. Incoming missiles from Russian submarines and warships ravage the Manhattan skyline. It's just another scenario for the multi-billion-dollar video games Call of Duty, which have sold more than 100 million games since the franchise's birth in 2003 The table shows the annual retail sales for Call of Duty video games from 2004 through 2010 . Create a scatter plot for the data. Based on the shape of the scatter plot, would a logarithmic function, an exponential function, or a linear function be the best choice for modeling the data? $$\begin{array}{cc} \hline \text { Year } & \begin{array}{c} \text { Retail Sales } \\ \text { (millions of dollars) } \end{array} \\ \hline 2004 & 56 \\ 2005 & 101 \\ 2006 & 196 \\ 2007 & 352 \\ 2008 & 436 \\ 2009 & 778 \\ 2010 & 980 \end{array}$$

In Exercises \(125-132,\) use your graphing utility to graph each side of the equation in the same viewing rectangle. Then use the \(x\) -coordinate of the intersection point to find the equation's solution set. Verify this value by direct substitution into the equation.. $$3^{x}=2 x+3$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.