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Use properties of logarithms to expand each logarithmic expression as much as possible. Where possible, evaluate logarithmic expressions without using a calculator. $$\ln \sqrt{e x}$$

Short Answer

Expert verified
The expanded form of the given expression \(\ln \sqrt{e x}\) is \(\frac{1}{2}+ \frac{1}{2} \ln x\).

Step by step solution

01

Identify the power rule property

The first task here is to see that \(\ln \sqrt{e x}\) fits into the power rule of logarithms, which is \(\ln a^m = m \ln a\). The expression inside the square root can be considered a half power, which will allow us to use the power rule.
02

Apply the power rule

Using the power rule, \(\ln a^m = m \ln a\), we can expand \(\ln \sqrt{e x}\) to be \(\frac{1}{2} \ln e x\).
03

Apply the product rule

Now apply the product rule of logarithms, which holds that \(\ln ab = \ln a + \ln b\). This lets us split \(\frac{1}{2} \ln e x\) into \(\frac{1}{2} (\ln e + \ln x)\).
04

Simplify \(\ln e\)

Knowing that \(\ln e = 1\), simplify the expression \(\frac{1}{2} (\ln e + \ln x)\) to be \(\frac{1}{2} (1 + \ln x)\), also rewrite it as \(\frac{1}{2} + \frac{1}{2} \ln x\).
05

Final Expanded Expression

Summarize your solution by determining the expanded form of the expression.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Natural Logarithm
The natural logarithm is a logarithmic function that is denoted as \( \ln(x) \), and it is fundamentally related to the constant \( e \), which is approximately equal to 2.71828. This special logarithm is so named because its base is \( e \), and it arises naturally in many areas of mathematics, particularly in problems dealing with growth and decay.

For example, if you have an amount that is growing continuously at a certain rate, the time it takes for the amount to grow to a specific value can be represented using the natural logarithm. It is also a key element in calculus, appearing in integrals and differential equations. In the context of expanding logarithmic expressions, understanding the natural logarithm is crucial, as it leads to simplifications such as \( \ln e = 1 \) because \( e \) is the base of natural logarithms. This property is exploited to simplify expressions as seen in the provided exercise.
Power Rule of Logarithms
The power rule of logarithms states that the logarithm of a number raised to an exponent is equal to the exponent multiplied by the logarithm of the number itself. Mathematically, it is expressed as \( \ln a^m = m \ln a \). This property is incredibly useful for simplifying complex logarithmic expressions, making them more manageable.

When dealing with square roots, remember that a square root is equivalent to raising a number to the \( \frac{1}{2} \) power. This is why in the exercise's step 1, the expression within the square root, \( \sqrt{ex} \), can be rewritten as \( (ex)^{\frac{1}{2}} \) leveraging the power rule. This transformation lays the foundation for expanding and simplifying the overall logarithmic expression.
Product Rule of Logarithms
The product rule of logarithms is a fundamental property that helps break down logarithms of products into more digestible parts. This rule states that the logarithm of a product is equal to the sum of the logarithms of the individual factors: \( \ln(ab) = \ln a + \ln b \).

By applying this rule to logarithmic expressions involving products, as seen in step 3 of the exercise, you can simplify the expression by writing it as a sum of separate logarithms. For instance, this rule transforms \( \ln(ex) \) into \( \ln e + \ln x \) which makes the expression easier to manage and opens up opportunities for further simplification like evaluating \( \ln e \) as 1, since the base of the natural logarithm is \( e \).
Logarithmic Expressions
Working with logarithmic expressions requires an understanding of various logarithmic properties and how to apply them correctly. These expressions can often be transformed and simplified using rules such as the power rule for exponents within a logarithm and the product rule for products inside a logarithm.

As you approach an expression like \( \ln \sqrt{ex} \), identifying and applying these properties systematically can expand the expression into a simpler or more useful form. It's much like untangling a knot—each logarithmic property you apply helps to pull the correct threads, leading you to a clearer understanding of the resulting expression. The final simplified form, such as \( \frac{1}{2} + \frac{1}{2} \ln x \) obtained in the exercise, is more than just an answer—it's a demonstration of how the properties of logarithms interact and flow together.

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Most popular questions from this chapter

In Exercises \(125-132,\) use your graphing utility to graph each side of the equation in the same viewing rectangle. Then use the \(x\) -coordinate of the intersection point to find the equation's solution set. Verify this value by direct substitution into the equation. $$5^{x}=3 x+4$$

Determine whether each statement makes sense or does not make sense, and explain your reasoning. I use the natural base \(e\) when determining how much money I'd have in a bank account that earns compound interest subject to continuous compounding.

Solve the equation \(x^{3}-9 x^{2}+26 x-24=0\) given that 4 is a zero of \(f(x)=x^{3}-9 x^{2}+26 x-24 .\) (Section 2.4 Example \(6)\)

From 1970 through \(2010 .\) The data are shown again in the table. Use all five data points to solve Exercises \(70-74\). $$\begin{array}{cc}\hline \begin{array}{c}x, \text { Number of Years } \\\\\text { after } 1969 \end{array} & \begin{array}{c}y, \text { U.S. Population } \\\\\text { (millions) }\end{array} \\ \hline 1(1970) & 203.3 \\\11(1980) & 226.5 \\\21(1990) & 248.7 \\\31(2000) & 281.4 \\\41(2010) & 308.7 \end{array}$$ Use your graphing utility's linear regression option to obtain a model of the form \(y=a x+b\) that fits the data. How well does the correlation coefficient, \(r,\) indicate that the model fits the data?

You take up weightlifting and record the maximum number of pounds you can lift at the end of each week. You start off with rapid growth in terms of the weight you can lift from week to week, but then the growth begins to level off. Describe how to obtain a function that models the number of pounds you can lift at the end of each week. How can you use this function to predict what might happen if you continue the sport?

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