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Find each product. $$(3 x+4)^{3}$$

Short Answer

Expert verified
The product of the given expression \((3x+4)^3\) is \(27x^3 + 108x^2 + 144x + 64\).

Step by step solution

01

Understand the Binomial theorem

The Binomial theorem allows us to expand expressions of the form \((a+b)^n\). For the cubic case \((a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3\). The coefficients 1, 3, 3, 1 are from the third row of Pascal's triangle.
02

Identify the terms in the expression

For the given expression \((3x+4)^3\), \(a = 3x\) and \(b = 4\).
03

Expand using the Binomial theorem

Substitute \(a = 3x\) and \(b = 4\) into the equation for the cubic binomial expansion. This yields \((3x)^3 + 3*(3x)^2*4 + 3*3x*(4)^2 + 4^3\).
04

Simplify the expression

Simplify each term to find the expanded form of \((3x+4)^3\). Which equals \(27x^3 + 108x^2 + 144x + 64\).

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