/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 86 Perform the indicated operations... [FREE SOLUTION] | 91Ó°ÊÓ

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Perform the indicated operations. Simplify the result, if possible. $$\left(4-\frac{3}{x+2}\right)\left(1+\frac{5}{x-1}\right)$$

Short Answer

Expert verified
\( \frac{4x^{2}+25x+34}{x^{2}+x-2} \)

Step by step solution

01

Apply distributive law

Apply the distributive law \(a(b + c) = ab + ac\) to both terms of the first bracket: \[(4-\frac{3}{x+2})(1+\frac{5}{x-1}) = 4 * 1 + 4 * \frac{5}{x-1} - \frac{3}{x+2} * 1 -\frac{3}{x+2} * \frac{5}{x-1}\]
02

Simplify

Re-arrange and simplify the obtained terms:\[4 + 20*\frac{1}{x-1} - 3*\frac{1}{x+2} - 15*\frac{1}{(x+2)(x-1)}\]
03

Simplify further

The fractions in the equation have different denominators, so before we can add or subtract them, we need to find a common denominator. The common denominator of \(x-1\), \(x+2\) and \((x+2)(x-1)\) is \((x+2)(x-1)\). So convert all terms into fractions with that denominator:\[4 + \frac{20(x+2)}{(x+2)(x-1)} - \frac{3(x-1)}{(x+2)(x-1)} - \frac{15}{(x+2)(x-1)}\]
04

Combine like terms

Now all terms have the same denominator, so they can be combined:\[\frac{4(x+2)(x-1) + 20*(x+2) - 3*(x-1) -15}{(x+2)(x-1)} \]
05

Simplify final expression

Simplify the resulting expression by calculating all terms in the numerator:\[\frac{4x^{2}+8x-4 + 20x +40 - 3x +3 - 15}{x^{2} + x -2}\]Then combine like terms in the numerator:\[\frac{4x^{2}+25x+34}{x^{2} + x -2}\]

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