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Chapter 6: Q.99 (page 396)

What values of 胃,f(胃)=sec(胃)does not exist

Short Answer

Expert verified

the value for the function does not exist when胃=(2n+1)蟺2

Step by step solution

01

Given information

We are given a functionf(胃)=sec(胃)

02

Explanation

We have,

f(胃)=sec(胃)f(胃)=1cos(胃)

The function does not exist when cos(胃)=0胃=(2n+1)蟺2

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Most popular questions from this chapter

In problems 13-20, Px,yis the point on the unit circle that corresponds to a real number t. Find the exact values of the six trigonometric functions of t.

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y=2csc13x-1

In Problems 4-6convert each angle in radians to degrees.

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Find the exact value of each expression. Do not use a calculator.

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