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Iff(x)=cosθ=0.3,findrole="math" localid="1647539382705" f(θ+π)

Short Answer

Expert verified

The value off(θ+π)=-0.3

Step by step solution

01

Step 1. Given information

f(θ)=cosθ=0.3

02

Step 2. Finding the value of f(θ+π)

For an angle θis standard position,let P=(x,y)be the point on the terminal side of θthat is also on the circle localid="1647539950698" x2+y2=r2.Then

localid="1647539956108" sinθ=yrcosθ=xrtanθ=yxcscθ=rysecθ=rxcotθ=xy

Consider f(θ)==cosθ=0.3

That is cosθ=xr=0.3

sothat x is positive

therefore,θis in 1st quadrants

Then θ+π is in the 2nd and 3rd quadrant so that xis negtive

Hence,

localid="1647539987909" f(θ+π)=-xr=-cosθ=-0.3

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