Q. 85 graph each function.f(x)=sin聽x0... [FREE SOLUTION]

91影视

Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 6: Q. 85 (page 411)

graph each function.
$f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$

Short Answer

Expert verified

The graph of the function $f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$ is

Step by step solution

Step 1. Given data

The given function is

$f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$

Step 2. Points of function

Determine coordinate of the points of the function $f (x) = \sin x$ in the interval $0 鈮� x < \frac{5 蟺}{4}$

Step 3. Points of the function

Determine the coordinate of points of the function $f (x) = \cos$ in the interval $\frac{5 蟺}{4} 鈮� x 鈮� 2 蟺$

Step 4. Graph of the function

Locate the points and connect them to plot the graph of $f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$

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91影视

graph each function.
$f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of function

Step 3. Points of the function

Step 4. Graph of the function

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91影视

graph each function.f(x)=sinx0鈮�x<5蟺4cosx5蟺4鈮�x鈮�2蟺

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of function

Step 3. Points of the function

Step 4. Graph of the function

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Logic and Functions

Calculus

Pure Maths

Applied Mathematics

Decision Maths

Mechanics Maths

Study anywhere. Anytime. Across all devices.

graph each function.
$f (x) = \{\begin{cases} \sin x & 0 鈮� x < \frac{5 蟺}{4} \\ \cos x & \frac{5 蟺}{4} 鈮� x 鈮� 2 蟺 \end{cases}$