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A point on the terminal side of an angle θin standard position is given. Find the exact value of each of the six trigonometric functions of θ:(-2,-2)

Short Answer

Expert verified

The exact value of each of the six trigonometric functions of θare,

sinθ=-12cosθ=-12tanθ=1cscθ=-2secθ=-2cotθ=1

Step by step solution

01

Step 1. Given information  

We are given a point (-2,-2).

We need to find the exact value of each of the six trigonometric functions.

02

Step 2. Concept  

Let (x,y)be a point on the terminal side of the angle θin the standard position, which is also on the circle x2+y2=r2. Then,

sinθ=yrcosθ=xrtanθ=yxcscθ=rysecθ=rxcotθ=xy

03

Step 3. Finding the value of r

We are given a point (-2,-2). Here x=-2,y=-2

To find r,

r=x2+y2r=(-2)2+(-2)2r=4+4r=8r=22

04

Step 4. Finding the exact values of the trigonometric function

The given point is (-2,-2). Here, x=-2,y=-2. We also have that, r=22

Then the six trigonometric functions are,

sinθ=yr=-222=-12cosθ=xr=-222=-12tanθ=yx=-2-2=1cscθ=ry=22-2=-2secθ=rx=22-2=-2cotθ=xy=-2-2=1

05

Step 5. Final Answer

The exact value of the six trigonometric functions of θare

sinθ=-12cosθ=-12tanθ=1cscθ=-2secθ=-2cotθ=1

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