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Find the exact value of each of the remaining trigonometric functions of θ.

²õ±ð³¦Î¸=-2,³Ù²¹²Ôθ>0

Short Answer

Expert verified

The exact values of trigonometric functions are,

²õ¾±²Ôθ=-32³Ù²¹²Ôθ=3³¦´Ç³Ùθ=33³¦²õ³¦Î¸=-233

Step by step solution

01

Step 1. Given Information

Given that the trigonometric function is ²õ±ð³¦Î¸=-2,³Ù²¹²Ôθ>0.To find the exact values of trigonometric function using substitution.

02

Step 2. Solving a equation

It implies that ²õ¾±²Ôθ<0in III quadrant. On using the equation,

sin2θ+cos2θ=1²õ¾±²Ôθ=±1-cos2θ

On substituting the value of ³¦´Ç²õθ=-12in the equation,

²õ¾±²Ôθ=-1--122=-1-14²õ¾±²Ôθ=-32

03

Step 3. Substitution

On substituting the value in equation,

³Ù²¹²Ôθ=yx=²õ¾±²Ô賦´Ç²õθ=-32-12³Ù²¹²Ôθ=3³¦´Ç³Ùθ=1³Ù²¹²Ô賦´Ç³Ùθ=33³¦²õ³¦Î¸=1²õ¾±²Ôθ=1-32³¦²õ³¦Î¸=-233

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