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Find the exact value of each of the remaining trigonometric functions of θ.

³Ù²¹²Ôθ=34,²õ¾±²Ôθ<0

Short Answer

Expert verified

The exact values of trigonometric functions are,

²õ±ð³¦Î¸=-54³¦´Ç²õθ=-45²õ¾±²Ôθ=-35³¦´Ç³Ùθ=43³¦²õ³¦Î¸=-53

Step by step solution

01

Step 1. Given Information

Given trigonometric functions is ³Ù²¹²Ôθ=34,²õ¾±²Ôθ<0.To find the exact values of trigonometric functions using substitution.

02

Step 2. Solve a equation

It implies that³¦´Ç²õθ<0and angle is III quadrant. On using the equationtan2θ+1=sec2θsec2θ=±tan2θ+1

03

Step 3. Substitution to find trigonometric function

On substituting the values,

²õ±ð³¦Î¸=-1+342=-1+916=-2516²õ±ð³¦Î¸=-54³¦´Ç²õθ=1²õ±ð³¦Î¸=1-54³¦´Ç²õθ=-45

04

Step 4. Substitution for sin, cot and csc functions

On using the equation of²õ¾±²Ôθ=±1-cos2θ²õ¾±²Ôθ=-1--452=-1-1625²õ¾±²Ôθ=-35³¦´Ç³Ùθ=1³Ù²¹²Ôθ=134³¦´Ç³Ùθ=43³¦²õ³¦Î¸=1²õ¾±²Ôθ=1-35³¦²õ³¦Î¸=-53

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