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Find the exact value of each of the remaining trigonometric functions of θ.

³¦²õ³¦Î¸=3,³¦´Ç³Ùθ<0.

Short Answer

Expert verified

The exact values are,

³¦´Ç²õθ=-223³Ù²¹²Ôθ=-24³¦´Ç³Ùθ=-22²õ±ð³¦Î¸=-324

Step by step solution

01

Step 1. Given information

Given that the trigonometric function is ³¦²õ³¦Î¸=3,³¦´Ç³Ùθ<0.To find the exact values using substitution.

02

Step 2. Pythagorean theorem

It implies that ²õ¾±²Ôθ=1³¦²õ³¦Î¸=13.Since ³¦´Ç³Ùθ<0,²õ¾±²Ôθ=13>0which implies that ³¦´Ç²õθ<0.On using the Pythagorean theorem,

sin2θ+cos2θ=1cos2θ=1-sin2賦´Ç²õθ=±1-sin2θ

03

Step 3. Substitution to find the values

On substituting the values in the above equation,

³¦´Ç²õθ=-1-(13)2=-1-19³¦´Ç²õθ=-223³Ù²¹²Ôθ=yx=²õ¾±²Ô賦´Ç²õθ=13-223³Ù²¹²Ôθ=-24

04

Step 4. Substitution to find the values of cot and sec

The reciprocal of cot is tan. On substituting the values,

³¦´Ç³Ùθ=1³Ù²¹²Ôθ=1-24³¦´Ç³Ùθ=-22²õ±ð³¦Î¸=1³¦´Ç²õθ=1-223²õ±ð³¦Î¸=-324

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