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Find the exact value of each of the remaining trigonometric functions of θ.

²õ±ð³¦Î¸=2,²õ¾±²Ôθ<0.

Short Answer

Expert verified

The exact values of the trigonometric functions are,

²õ¾±²Ôθ=-32³Ù²¹²Ôθ=-3³¦´Ç³Ùθ=-33³¦²õ³¦Î¸=-233

Step by step solution

01

Step 1. Given Information

Given that the function is ²õ±ð³¦Î¸=2,²õ¾±²Ôθ<0.To find the exact values using substitution.

02

Step 2. Phythagorean identity

It implies that ³¦´Ç²õθ=1²õ±ð³¦Î¸=12. Since ²õ¾±²Ôθ<0,³¦´Ç²õθ=12>0.On using Phythagorean identity as sin2θ+cos2θ=1. On using this equation to solve for ²õ¾±²Ôθ,

sin2θ+cos2θ=1²õ¾±²Ôθ=±1-cos2θ

On substituting the values,

²õ¾±²Ôθ=-1-(12)2=-1-14=-34²õ¾±²Ôθ=-32

03

Step 3. Definition of unit circle

The definition of unit circle is ²õ¾±²Ôθ=y,³¦´Ç²õθ=x.

³Ù²¹²Ôθ=yx³Ù²¹²Ôθ=²õ¾±²Ô賦´Ç²õθ=-3212³Ù²¹²Ôθ=-3³¦´Ç³Ùθ=1³Ù²¹²Ôθ=1-3³¦´Ç³Ùθ=-32³¦²õ³¦Î¸=1²õ¾±²Ôθ=-132=-23³¦²õ³¦Î¸=-233

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