Precalculus Enhanced with Graphing Utilities

Sullivan

$Math Studyset 91影视 Explanations$ Math

6th Edition 路 1200 pages

ISBN: 9780321795465

Chapter 6: Q. 49 (page 419)

graph each function
$f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$

Short Answer

Expert verified

The graph of $f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$ is

Step by step solution

Step 1. Given data

The given function is

$f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$

Step 2. Points of f(x)=tan x

Consider different values of x from $[0, \frac{蟺}{2})$ for $f (x) = \tan x$ and determine several coordinates of points

Step 3. Points of f(x)=sec x

Consider different values of xfrom $(\frac{蟺}{2}, 蟺)$ for $f (x) = s e c x$ and determine several coordinates of points

Step 4. Graph of the function

Use the coordinates of points and Plot the graph of $f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$

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91影视

graph each function
$f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of f(x)=tan x

Step 3. Points of f(x)=sec x

Step 4. Graph of the function

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91影视

graph each functionf(x)=tanx0鈮�x<蟺20x=蟺2secc蟺2<x鈮�蟺

Short Answer

Step by step solution

Step 1. Given data

Step 2. Points of f(x)=tan x

Step 3. Points of f(x)=sec x

Step 4. Graph of the function

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Calculus

Logic and Functions

Statistics

Discrete Mathematics

Probability and Statistics

Mechanics Maths

Study anywhere. Anytime. Across all devices.

graph each function
$f (x) = \{\begin{cases} \tan x & 0 鈮� x < \frac{蟺}{2} \\ 0 & x = \frac{蟺}{2} \\ s e c c & \frac{蟺}{2} < x 鈮� 蟺 \end{cases}$