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In Problems 16–23, find the exact value of each of the remaining trigonometric functions.

secθ=3,3π2<θ<2π

Short Answer

Expert verified

The exact values of the remaining trigonometric functions of secθ=3are,

role="math" localid="1646417178742" sinθ=-223cosθ=13tanθ=-22cscθ=-324cotθ=-122=-24

Step by step solution

01

Step 1 Given expression is,

secθ=3and 3π2<θ<2π.

So,θlies in the fourth quadrant where secθis positive.

Let αbe the reference angle for θthen secθ=ra=secα.

So,secα=31=OppositeAdjacent

Use the values r=3,a=1to construct a triangle.

From the figure, we obtainb=22.

02

Step 2 Now calculate the remaining trigonometric functions.

The exact values of the remaining trigonometric functions of the reference angle αare,

localid="1646417520233" sinα=br=223cosα=ar=13tanα=ba=22cscα=rb=324cotα=ab=122=24

03

Step 3 The exact values of the remaining trigonometric functions of the angle θ are,

sinθ=-223cosθ=13tanθ=-22cscθ=-324cotθ=-122=-24

These are the exact values of the remaining trigonometric functions.

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