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Chapter 6: Q 125. (page 383)

If friction is ignored, the time t (in seconds) required for a block to slide down an inclined plane is given by the function

t胃=2agsin胃cos胃

where a is the length (in feet) of the base and g 32 feet per second per second is the acceleration due to gravity. How

long does it take a block to slide down an inclined plane with base a = 10 feet when,

(a) 胃=30掳

(b) 胃=45掳

(c)胃=60掳

Short Answer

Expert verified

(a) t胃=2083

role="math" localid="1646650348689" (b)t胃=2083(c)t胃=54

Step by step solution

01

Step 1. Given information .

Consider the given value of a = 10 and g = 32 .

02

. (a) Formula used .

Formula used to find the value .

t胃=2agsin胃cos胃

Substitute the value a=10,g=32,胃=30掳in formula

t30掳=2脳1032脳12脳32t30掳=2083

03

Step 3.  Formula used to find tθ if θ=45°

The formula is t胃=2agsin胃cos胃

Substitute the values in formula .

t45掳=2脳1032脳32脳12t45掳=2083

04

Step 4. Formula used to find tθ if ϑ=60° .

The formula is

t胃=2agsin胃cos胃

Substitute the value of a,g,胃.

t60掳=2脳1032脳12脳12t60掳=54

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