/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 124. The projectile is fired at an an... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The projectile is fired at an angle of 50° to the horizontal with an initial speed of 200 feet per second.Find the range and height.

Short Answer

Expert verified

The range is 4019.5 and height is 1150041 .

Step by step solution

01

Step 1. Given information .

Consider the given initial speed 200 meter per second and angle is50°.

02

Step 2. Formula used .

The formula used to find range is Rθ=νo2sin2θgand to find height isHθ=νo2sinθ22g.

03

. Finding range and height.

Substitute the values in formula where initial speed νo=200,θ=50°.

Rθ=νo2sin2θgRθ=2002sin2×50°9·8Rθ=4019·5

Further simplify.

Hθ=νo2sinθ22gHθ=2002sin50°22×9·8Hθ=40000×0·766219·6Hθ=1150041

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.