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91Ó°ÊÓ

Use the periodic and even–odd properties.

Iff(θ)=secθand f(a)=-4, find the exact value of :

(a) f(-a)

(b) f(a)+f(a+2Ï€)+f(a+4Ï€).

Short Answer

Expert verified

(a) The value of f(-a)is-4.

(b) The value of f(a)+f(a+2Ï€)+f(a+4Ï€)is-12.

Step by step solution

01

Step 1. Given Information  

We have given that following function :-

f(θ)=secθand role="math" f(a)=-4.

We have to find the value of f(-a)and value of f(a)+f(a+Ï€)+f(a+4Ï€).

To find value of f(-a)we will use even-odd properties and to find the value of f(a)+f(a+2Ï€)+f(a+4Ï€)we will use periodic properties.

02

Step 2. Part (a). To find value of f(-a)

We have given that :-

f(θ)=secθand f(a)=-4.

We know that :-

sec(-θ)=secθ.

Now put θ=-a, in f(θ)=secθ, then we have :-

f(-a)=sec(-a)⇒f(-a)=sec(a)⇒f(-a)=f(a)

Put f(a)=-4, then we have :-

f(-a)=-4.

This is the required value.

03

Step 3. Part (b). To find value of  f(a)+f(a+2π)+f(a+4π)

We have given that :-

f(θ)=secθ.

We know that secant function is of period 2Ï€.

This gives us :-

sec(θ+2πk)=secθ, for any integer k.

Now :-

localid="1647095654962" f(a)+f(a+2π)+f(a+4π)=sec(a)+sec(a+2π)+sec(a+4π)⇒f(a)+f(a+2π)+f(a+4π)=sec(a)+sec(a)+sec(a)⇒f(a)+f(a+2π)+f(a+4π)=3sec(a)⇒f(a)+f(a+2π)+f(a+4π)=3f(a)

Put f(a)=-4, then we have :-

f(a)+f(a+2π)+f(a+4π)=3(-4)⇒f(a)+f(a+2π)+f(a+4π)=-12

This is the required value.

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