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In problems use the periodic and even–odd properties.

If f(θ)=sinθand role="math" localid="1646574788292" f(a)=13, find the exact value of :

(a) f(-a)

(b) f(a)+f(a+2Ï€)+f(a+4Ï€).

Short Answer

Expert verified

(a) The value of f(-a)is 13.

(b) The value of f(a)+f(a+2Ï€)+f(a+4Ï€)is1.

Step by step solution

01

Step 1. Given Information

We have given that following function :-

f(θ)=sinθand f(a)=13.

We have to find the value off(-a) and value of f(a)+f(a+2Ï€)+f(a+4Ï€).

To find value off(-a)we will use even-odd properties and to find the value off(a)+f(a+2Ï€)+f(a+4Ï€)we will use periodic properties.

02

Step 2. Part (a). To find value of f(-a)

We have given that :-

f(θ)=sinθ.

Put localid="1646838403718" θ=-a, then we have :-

f(-a)=sin-a.

We know that sine function is an odd function, that is :-

sin-θ=-sinθ.

So that sin-a=-sina.

This gives us :-

f(-a)=-sinaorf(-a)=-f(a)

We have given that f(a)=13.

By putting this value we have :-

localid="1646838673711" f(-a)=-13.

This is the required value.

03

Step 3. Part (b) To find value of f(a)+f(a+2π)+f(a+4π)

Given that :-

f(θ)=sinθ.

We know that sine function is periodic for period 2Ï€.

That is:-

sinθ+2πk=sinθ, for any integer k.

So that we have :-

localid="1646839059213" f(θ)+f(θ+2π)+f(θ+4π)=sinθ+sinθ+2π+sinθ+4π⇒f(θ)+f(θ+2π)+f(θ+4π)=sinθ+sinθ+sinθ⇒f(θ)+f(θ+2π)+f(θ+4π)=3sinθ⇒f(θ)+f(θ+2π)+f(θ+4π)=3f(θ)

Now take localid="1646839312516" ain place of θ, then we have :-

f(a)+f(a+2Ï€)+f(a+4Ï€)=3f(a).

We have f(a)=13.

By putting this value we have :-

localid="1646871511245" f(a)+f(a+2π)+f(a+4π)=3×13⇒f(a)+f(a+2π)+f(a+4π)=1

This is the required value.

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