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In Problems 53–56, write a system of linear inequalities for the given graph.

Short Answer

Expert verified

The solution is

x+y≤6x≤4x≥0y≥0

Step by step solution

01

Step 1. Given information

The graph is in the first quadrant so the values arex≥0&y≥0.

02

Step 2. Given points 

The given points of the line are (0,6)& (4,2).

slope m=(y2-y1(x2-x1)m=(2-6)(4-0)m=-44m=-1

03

Step 3. Line equation

y-y1=m(x-x1)y-0=-1(x-6)y=-x+6x+y=6

Since the origin lies in the graph so the function is x+y≤6.

04

Step 4. Llast line

The line parallel to y-axis equation is x=k

here k=4so the equation is localid="1646936164319" x=4

The point origin lies in the graph so inequality isx≤4.

05

Step 5. Solution

By considering all equations the inequalities are

x+y≤6x≤4x≥0y≥0

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