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Chapter 11: Q. 48 (page 773)

Solve the system. Use any method you wish.

x2-xy-2y2=0xy+x+6=0

Short Answer

Expert verified

The solution of system of equations are 3,-3,-2,2.

Step by step solution

01

Step 1. Given information.

Consider the given question,

x2-xy-2y2=0......(i)xy+x+6=0......(ii)

Divide equation (i) by y2,

x2y2-xyy2-2y2y2=0x2y2-xy-2=0xy-2xy+1=0x=2y,y

02

Step 3. Substitute the values of x in equation (ii).

Substitute x=yin equation (ii),

yy+y+6=0y2+y+6=0y=-3,2

Substitute x=2yin equation (ii),

role="math" localid="1646937140202" 2yy+2y+6=02y2+2y+6=0y2+y+3=0

There is no solution for this value.

Therefore, the solution sets are3,-3,-2,2.

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