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91Ó°ÊÓ

Write the partial fraction decomposition of each rational expression.

x3(x2+16)3

Short Answer

Expert verified

The partial fraction decomposition is x3(x2+16)3=x(x2+16)2+−16x(x2+16)3

Step by step solution

01

Step 1. Given Information. 

The rational expression is,

x3(x2+16)3=Ax+Bx2+16+Cx+D(x2+16)2+Ex+F(x2+16)3

x3(x2+16)3=(x2+16)2(Ax+B)+(x2+16)(Cx+D)+Ex+F(x2+16)3

Therefore,

x3=(x2+16)2(Ax+B)+(x2+16)(Cx+D)+Ex+F

x3=x5A+x4B+32x3A+x3C+32x2B+x2D+256xA+16xC+xE+256B+16D+F

Therefore,

A=0B=032A+C=132B+D=0256A+16C+E=0256B+16D+F=0

02

Step 2. Partial Fraction Decomposition.  

Decompose the rational fraction, we get,

A=0,B=0,C=1,D=0,E=−16,F=0

Therefore,

role="math" localid="1647535930996" x3(x2+16)3=x(x2+16)2+−16x(x2+16)3

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