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In Problems 31-40, each matrix is nonsingular. Find the inverse of each matrix.

102-1231-10

Short Answer

Expert verified

The inverse of the matrix102-1231-10is,3-2-43-2-5-112.

Step by step solution

01

Step 1. Given information

102-1231-10

We have to find the inverse of the given matrix.

02

Step 2. First find the augmented matrix A|I3

A|I3→102100-1230101-10001

Now transform it into I3|A-1using roe transformations.

102100-1230101-10001→R2→R2+R1;R3→R3-R11021000251100-1-2-101→R2→R2+R31021000130110-1-2-101→R3→R3+R2102100013011001-112→R1→R1-2R3;R2→R2-3R31003-2-40103-2-5001-112

03

Step 3. The augmented matrix A|I3 is now in the reduced echelon form and the identity matrix I3 is on the left side of the vertical bar and A-1 is on the right side of the vertical bar.

A-1=3-2-43-2-5-112.

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