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91Ó°ÊÓ

Graph each equation of the system. Then solve the system to find the points of intersection.

3x2-2y2+5=02x2-y2+2=0

Short Answer

Expert verified

The point of intersection is (1,2),(1,-2),(-1,2),(-1,-2).

Step by step solution

01

Step 1. Given information

3x2-2y2+5=02x2-y2+2=0

02

Step 2. Graphing each equation

3x2-2y2+5=0


2x2-y2+2=0

03

Step 3. Calculation of intersection point

Consider,3x2-2y2+5=0....(1)2x2-y2+2=0.......(2)Multiply2witheq.2andsubtractfromeq.1weget-x2+1=0x=±1substitutevalueofxineq.1togetyx=13-2y2+5=0y=±2x=-1y=±2

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