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Chapter 11: Q. 3 (page 793)

In Problems 1鈥�10, solve each system of equations using the method of substitution or the method of elimination. If the system has no solution, say that it is inconsistent.

x-2y-4=03x+2y-4=0

Short Answer

Expert verified

The solution of the system is (2,-1).

Step by step solution

01

Step 1. Given Information

We are given a system of equations x-2y-4=03x+2y-4=0.

We need to solve the system of using the method of substitution or the method of elimination.

02

Step 2. Eliminate y and solve for x

Add the two equations and eliminate y.

x-2y-4+3x+2y-4=04x-8=0

Now solve the equation for x

4x-8+8=0+84x=8x=2

03

Step 3. Solve for y

Substitute 2for xin the first equation and solve for y.

x-2y-4=02-2y-4=0-2y-2=0-2y=2y=-1

So the solution is given by the ordered pair 2,-1.

04

Step 4. Check the solution 

Substitute 2for xand -1for yin both the equations.

x-2y-4=02-2路(-1)-4=02+2-4=04-4=00=03x+2y-4=03路2+2路(-1)-4=06-2-4=06-6=00=0

So both the equations are satisfied. Thus the found solution is correct.

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Most popular questions from this chapter

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